Listen Now Download as mp3 from the show Checking the Atmosphere and Changing the Climate QuestionJane BrittainLong asked: Hi, I have been trying to find out an answer to this question ever since I did Physics Olevel in 1985!
If you were an average man, say 6 feet tall and weighing about 12 stone, if you took hold of a spoiler on the back of a car, how fast would the car have to go to ensure you were actually lifted off your feet and flying behind it? I know this is very hypothetical but I want to know!!! There must be a mass/speed equation going on but I am not a scientist and my two boys want to know, too!
regards,
Jane
AnswerWe posed this question to Dr Hugh Hunt from the University of Cambridge... Hugh  Well I suppose if we’re trying to figure out how fast you need to go in a car and somebody grabbed a hold at the back, and you’re try to lift them up off the ground, it’s all about aerodynamic drag. The aerodynamic drag, there's a formula for it which is the half ρ V^{2} multiplied by frontal area, multiplied by drag coefficient. Now ρ is the density of air and that's 1.2 kg/cubic metre – that's easy. V is the speed of the car in meters per second. A is the frontal area of the person. Now, let’s make a rough guess, it’s a 10stone person, so they're reasonably slim, a couple of meters high, say on average, 20 centimetres wide, wider in the middle, thinner at the legs. It’s as good guess as any, so that gives them a frontal area of 0.4 square meters. The drag coefficient, well, we need to make another guess here because the air behind the car is very turbulent. It’s impossible to know what the drag coefficient would be, but let’s say 0.5 – that's a reasonable figure, I think. So if you do these sums, so the drag force is roughly equal to the weight of the person, then you end up needing to drive at about 160 miles an hour. Well, is that reasonable? Look, it’s such a complicated airflow behind the car and there are questions about when does a drag become lift? Once the person’s out at an angle of 45 degrees then you might start thinking, we need to calculate the lift on the person rather than the drag on a person. We could have lots of arguments over this over a few beers if you want, but at least that's my start up calculation. Multimedia
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CommentsTerminal velocity for an adult is about 125mph in the spreadeagled position with belly (down) into the air flow ... You'd be 90% horizontal if the car kept accelerating at about 10g (98.1 m/s/s), although that sort of acceleration is a bit unlikely, even with a spoiler Geezer, Mon, 14th Feb 2011 Don't forget to hold the spoiler upside down. Bored chemist, Mon, 14th Feb 2011 I don't think it is an acceleration problem as much as a lift and drag problem.

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