Post by: f.point on 07/01/2016 10:44:16
Odd proportion angles (there is a proportion of the steam angles) of the element 3 (which may be 5,7,9, ...) and the base angle
(which can be any angle which is obtainable by means of compass and straightedge)The angle CAB
can be obtained with a compass and unmarked ruler, he added angles (each have ) DAC and EAD, obtained angle EAB 
is the starting angleMerge points E (D, C, B) and get a longer ED (DC, CB)
Along the DC from the point C draw is normal that intersects the segment AB, the intersection is a point G
Divider AG and from point G draw a circular arc to a longer EA and H get the point, and the arc GH, join the dots G and H and get along GH
Longer GH (ED, DC, CB) are equal, the arc EB's first circular arc can be made smaller or larger with a constant radius AB, arc GH is the second circular arc can be made smaller or larger with a constant radius AG
INCREASING THE ANGLE
the starting angle EAB add angle FAE
get the angle FAB 
- continued in the next post
Post by: chris on 07/01/2016 11:19:11
Post by: f.point on 12/01/2016 15:58:08
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Required accessories - pencil, compass, unmarked straightedge
basic angle - can be any angle that can be construction using compass and unmarked straightedge, angle CAB
starting angle - sum of 2, 3, 4, 5, ... basic angles , EAB
sum angles CAB
DAC EAD difference angle - the angle which increases or decreases the starting angle. difference starting angle and the angle of whom do not know the measure , this angle is known to see a procedure HAB
straightedge AB is divided into three parts AF , how we have a basis in the angles starting angle
divider AF from point A the circular arc FG
section straightedge AH the circular arc FG , point I
straightedges FG , ED
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will continue - if there are errors
Post by: evan_au on 13/01/2016 08:20:21
This website is about asking and answering questions, so please phrase the thread as a question (even if it is "Is this a valid way to trisect an angle?").
Post by: f.point on 20/01/2016 09:53:28
starting angle EAB
consists of the sum of the angles CAB DAC 
EAD DC straightedge the normal to the point D , gets the point F
AF divider from point A, we get the point G
divider AB from point F, divider AB from point G, we get the point H
HG divider from point H, creates a circular arc FG
difference angle IAB
section IA and longer circular arc FG is a point J
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Post by: Bored chemist on 20/01/2016 21:10:10
You construct a triangle of 60 degrees and the difference is 15 which is a third of 45.
However that's not generally very useful.
Being able to construct an angle like 135 degrees by trebling some other angle, then dividing it back into three parts is even less use.
What would be interesting would be a general way of splitting an angle into 3 equal parts.
However that problem has been proven to be impossible.
Why spend time on it?
Post by: alysdexia on 21/01/2016 13:43:12
Being able to construct an angle like 135 degrees by trebling some other angle, then dividing it back into three parts is even less use.
What would be interesting would be a general way of splitting an angle into 3 equal parts.
However that problem has been proven to be impossible.
Why spend time on it?
Only with a compass and edge, not with a ruler. What if one uses two or three compasses at a time?
Anyway one could triple any angle, put a set of those angles in a table, then use that table as the ruler.
Post by: f.point on 30/01/2016 16:50:15
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bisection angle DAC is obtained by point J
along AJ
GF section circular arc and along the AJ, obtained point L
AF divider, from the point J, we get the point O
divider AF, from point A circle c1
divider GL, from the point J, the circuit d1, get the points P and Q
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