Naked Science Forum
Non Life Sciences => Chemistry => Topic started by: Paul D on 03/02/2006 15:21:43
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Hi all,
this is my first post on the forum so i hope somebody out there can help me.
I have a reaction mixture of NaClO3 + NaCl + NaIO3 in mildly acidic conditions (pH 6)that gives off Cl2. Can anybody find an appropriate equation for this reaction. I have busted my gut for the past 2 weeks without success.
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Im sorry I cannot imagine the reaction product from this.
What acid did you use? Are you sure it is Cl2 that is given off?
some points:
-NaCl is an ionic bond hard to break.
-The bond between oxygen and iodine is more polar than with chlorine,
electronegativities:
O(3.44), Cl(3.16), I(2.66)
O - Cl = 3.44 - 3.16 = 0.28
O - I = 3.44 - 2.66 = 0.78
It could be chlorine or oxygen that is released.
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Yes it is definitely chlorine and I can use any acid nitric hydrochloric or sulphuric.
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are you sure this is one balanced reaction because from looking at the used products it makes me think of the preparation of NaClO3 , could it be that the acid is making this process reversing because of the acid? I don't think so, this reaction seems unlikely!
NaClO3 preparation
Na+ + Cl- elektrolyse gives:
-Na(solid) + H20 gives NaOH
- NaOH + Cl2(elektrolyse)
gives NaCLO(high T) gives NaClO3
and if what you say is true then surely the I2 would come free before the Chloride because of elektronegativity
grtz
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I think I found something for you:
http://en.wikipedia.org/wiki/Chlorine_dioxide
http://en.wikipedia.org/wiki/Sodium_chlorate
hope it helps.
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Yes I think that might be it, thanks