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Unfortunately, however interesting that may or may not be, it isn't an equation.
Quote from: jeffreyH on 04/01/2016 18:18:48Unfortunately, however interesting that may or may not be, it isn't an equation.zero
All the photons energy is kinetic. Therefore E is all kinetic energy. Since E = hf and all the gravitational forces cancel there is no shift applied to the frequency f at the centre of gravity. This indicates that the frequency is highest at this point and thus has a maximum energy. The shift of the wavelength is to the red end of the spectrum in any direction away from the centre of gravity. If we apply this to a particle with mass we cannot say the same as the relationship between wavelength and energy is now velocity dependent. This does imply that the highest energy for any particular photon is at the centre of gravity. Dependent upon the initial energy of the photon when emitted. The centre of gravity of large bodies can therefore be a source of energy if photons are passed through it
This does imply that the highest energy for any particular photon is at the centre of gravity. Dependent upon the initial energy of the photon when emitted. The centre of gravity of large bodies can therefore be a source of energy if photons are passed through it.
Quote from: jeffreyH on 04/01/2016 23:38:26This does imply that the highest energy for any particular photon is at the centre of gravity. Dependent upon the initial energy of the photon when emitted. The centre of gravity of large bodies can therefore be a source of energy if photons are passed through it.That doesn't quite compute to me. However it is something easily tested. The Centre of Mass of the Pluto/Charon binary is outside the radius of both bodies.If amplification of EMR is possible by photons passing through the centre of Mass then this should be detectable.
That doesn't quite compute to me. However it is something easily tested. The Centre of Mass of the Pluto/Charon binary is outside the radius of both bodies.If amplification of EMR is possible by photons passing through the centre of Mass then this should be detectable
That is not the center of mass. That is the focal balanced attraction point between the two masses. The boundary point of equal attraction to each COA. That position is also related to the mass of each body. Its the equal dilation point between the two bodies.
Lookup UV spectrum of the pluto-charon system.
Quote from: jeffreyH on Today at 13:19:45Lookup UV spectrum of the pluto-charon system.Jeffrey, you have obviously found something in support of your claim.I'm about to leave for an operation on my back later but will certainly look into it on my return.
Imagine a mass that is a perfect sphere with a perfectly spherical cavity at the centre. If you slice it into two hemispheres then the slice can be said to be coincident with the x/y plane with a z-axis perpendicular to that plane and with the COG at the origin. If motion is constrained to move along the z-axis only, then the only point of equilibrium is at the COG. If the point remains at the centre of gravity the sphere is rotationally symmetric. You cannot say this about a centre of gravity that lies outside the body of a system. So the Pluto-Charon system is a very bad choice of laboratory.
Quote from: Thebox on 04/01/2016 23:03:37Quote from: jeffreyH on 04/01/2016 18:18:48Unfortunately, however interesting that may or may not be, it isn't an equation.zeroAll the photons energy is kinetic. Therefore E is all kinetic energy. Since E = hf and all the gravitational forces cancel there is no shift applied to the frequency f at the centre of gravity. This indicates that the frequency is highest at this point and thus has a maximum energy. The shift of the wavelength is to the red end of the spectrum in any direction away from the centre of gravity. If we apply this to a particle with mass we cannot say the same as the relationship between wavelength and energy is now velocity dependent. This does imply that the highest energy for any particular photon is at the centre of gravity. Dependent upon the initial energy of the photon when emitted. The centre of gravity of large bodies can therefore be a source of energy if photons are passed through it.
Quote from: jeffreyH on 05/01/2016 23:47:00Imagine a mass that is a perfect sphere with a perfectly spherical cavity at the centre. If you slice it into two hemispheres then the slice can be said to be coincident with the x/y plane with a z-axis perpendicular to that plane and with the COG at the origin. If motion is constrained to move along the z-axis only, then the only point of equilibrium is at the COG. If the point remains at the centre of gravity the sphere is rotationally symmetric. You cannot say this about a centre of gravity that lies outside the body of a system. So the Pluto-Charon system is a very bad choice of laboratory.No worries.I give up. You suggested a possibility for an Electromagnetic amplification effect at the "centre of gravity".All I did was point you towards an easily accessible "centre of gravity" where the hypothesis could be tested.You are now putting so many restrictions on what constitutes a "centre of gravity", that you are effectually putting the original claim in the totally untestable bracket. There is a very clear scientific definition of what constitutes a "centre of gravity".When the goal posts start to move to suit one's views, it is a signal for me to leave a thread.Enjoy...