Post by: simplified on 23/12/2012 06:58:03
T=T_o/(1-2GM/Rc^2)^[(1+v^2/c^2)/2]
v - speed of atomic clock in gravitation
Is this equation exacter than Einstein's equation?
Post by: CliffordK on 23/12/2012 12:55:33
T =
I think.
(oops, I think I got the "1 -" in the wrong place, fixed).
Post by: simplified on 23/12/2012 18:14:33
T=T_o/(1-2GM/Rc^2)^[(1+v^2/c^2)/2]T=
T =
I think.
(oops, I think I got the "1 -" in the wrong place, fixed).
Post by: CliffordK on 23/12/2012 23:28:12
= 
However, it is not the same as:
= 
Unless I missed something in the original equation.
I'll try to understand your equation later, but I assume you are doing something similar to the Lorentz Transformation (http://en.wikipedia.org/wiki/Lorentz_transformation).
Velocity is a function of time and distance, thus
Time is a function of velocity and distance.
Hmmm,
So, is T0 a constant (initial time), or is it a function (the time function independent of gravitation effects)?
M is the mass of the planet.
G is the gravitational constant.
R is distance from the center of the planet.
c is the speed of light.
v is the velocity of whatever is carrying the clock.
Of course, if you think of Earth, the planet surface where most of our clocks are is spinning and moving.
Anyway, why don't you post a little about what you're trying to accomplish, and the derivation of your equation.
Post by: simplified on 24/12/2012 17:35:49
1-v^2/c^2=(c^2-v^2)/c^2
1+v^2/c^2=(c^2+v^2)/c^2
What is wrong?I think you don't know the mathematical rule.Maybe the rule works only in Russia,I don't know.Even my calculator works so.
You want to know equation derivation.I don't like gravitational length contraction.If the equation is right then we don't need gravitational length contraction.Therefor I have created it.
Post by: CliffordK on 25/12/2012 04:32:41
I had just misread your exponent earlier.
Thinking:
^[(1+v^2/c^2)/2] = ^[((1+v^2)/c^2)/2]
[:-\]
See, TEX is so much easier [;)]
Post by: simplified on 02/01/2013 19:05:03
http://en.wikipedia.org/wiki/Gravitational_time_dilation
Hmmm,
So, is T0 a constant (initial time), or is it a function (the time function independent of gravitation effects)?
http://hyperphysics.phy-astr.gsu.edu/hbase/hframe
Post by: Raphael on 21/01/2013 21:04:13
http://www.upscale.utoronto.ca/GeneralInterest/Harrison/GenRel/GenRel.html
this puzzle is found at the bottom of the page....
Quote
A bucket of water has a spring soldered to the bottom, as shown. A cork is attached the spring, and is therefore suspended under the surface of the water.
You are on top of the CN tower, holding the bucket, and step off. While falling towards the ground, do you see the cork move towards the top of the water, towards the bottom of the bucket, or stay where it is relative to the bucket and the water?
namaste
Post by: simplified on 24/01/2013 17:26:13
delta of Archimedes' force=pv*delta of g
But force of the spring will increase too
delta of force of the spring=2delta of energy of the spring :-\