Do electrically-charged objects have an "electromagnetic escape velocity"? Here's an example for clarification of my question:

Imagine a gigantic, negatively charged sphere, about the size of Earth. There is a positively charged rocket resting on the surface of this sphere. The strength of electromagnetic attraction between the giant sphere and the rocket is equal to 1 G (assume here that gravity is irrelevant). That 1 G of force results from the electrical attraction between the rocket and the sphere, not gravity. For all intents and purposes, this has the same effect as an uncharged rocket sitting on Earth, where gravity produces 1 G instead of electromagnetism, correct?

Now, let's assume that this rocket wants to take-off of the sphere and get into space. Since the strength of electrical attraction is 1 G, just like on Earth, does the rocket have to attain a certain "escape velocity" to get into space and escape the electromagnetic field? Would it be the same as the Earth's gravitational escape velocity of about 25,000 mph?

From this idea, I was wondering if there might be an electromagnetic analog of a blackhole. Just as a blackhole has so much gravity that any object with mass cannot escape from it, even by going light-speed, might there also be an object that has so much electrical charge that no electrically-charged object can escape from its pull, even by going light-speed? The situation would be reversed for objects that have the same charge as this "Massively-Charged Object" (MCO), in which the resultant repulsion is so great that they could not approach it even at light-speed.

I'm not exactly sure how to make an MCO, since squishing large numbers of electrically-charged particles together into a blackhole-like density would be strongly opposed by repulsion.

Could an MCO exist, theoretically speaking?