Photons can be represented entirely as an electromagnetic field vectors in space and time with a unique frequency. This frequency is a measure of its energy. E=hν (h being Planck constant). The frequency is space time dependent (Doppler effect). Hence the photon energy is dependent and uniquely dependent on space time.

(one interesting point is that space time can be define relatively to a photon energy field)

If you travel in a parallel direction to the photon direction, and accelerate until you reach the speed of light relative to your initial position, the photon energy you measure will increase until it is infinite (when you travel at C, theoretically speaking because we all know it is an unattainable speed) according to the frequency shift relative to your change in velocity. As your velocity increase, your time measurement decrease until it stop when you reach C. So, if your time measurement decrease, you measure a higher photon frequency.

On the contrary, if you accelerate in the opposite direction to the photon direction, the photon energy you will measure will decrease until it reaches zero at the moment you travel at the speed of light relative to your initial position.

My question is: is there an accelerated trajectory where you will always measure the same photon energy? Because if there is one or more, it means the photon needs a coupling particle or photon traveling in another direction in order to keep the information of space time... Maybe there is not because of the variation in the elecromagnetic field of the photon relatively to all possible accelerated trajectory...?