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Author Topic: Who wants to learn a new conservation law?  (Read 17591 times)

Offline jartza

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« Reply #25 on: 14/11/2010 11:15:36 »
Nearby  Sirius B a photon is approaching to it, this photon is receiving energy. Is this event reducing mass of Sirius B?

No, Sirius B doesn't have any clue that there is a photon approaching. This is according to the "information can't travel faster than c" -thing. 
 

Offline simplified

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« Reply #26 on: 14/11/2010 14:19:02 »
I wasn't asking about speed. Sirius B increases frequency of wave of an approaching photon.Does it increase energy of the photon? If yes, then where does the energy come from?
 

Offline jartza

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« Reply #27 on: 14/11/2010 19:42:48 »
I wasn't asking about speed. Sirius B increases frequency of wave of an approaching photon.Does it increase energy of the photon? If yes, then where does the energy come from?

Does the energy come from Sirius B?

No.

 

Offline jartza

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« Reply #28 on: 15/11/2010 00:27:53 »
Nearby  Sirius B a photon is approaching to it, this photon is receiving energy. Is this event reducing mass of Sirius B?


Falling is a straightforward thing. No energy change happens.

 

Offline JP

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« Reply #29 on: 15/11/2010 04:08:24 »
I think we can safely say this has strayed into New Theories territory...

Are you going to elaborate on mass-energy relationship?
That's what I expected next in this discussion.



I think I elaborated a bit on it already.  No offense, but I find your posts to be a bit confusing (it may be a language issue?), which is why I haven't been able to answer them better.  Do you have a specific question about mass and energy and their relationship?
 

Offline jartza

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« Reply #30 on: 15/11/2010 12:27:57 »

Let's attach some radioactive material on the center part of a big flywheel.
The radioactive stuff starts heating the flywheel. No heat is lost to anywhere else.
The flywheel is frictionless. Then we make the flywheel spin. What can we say about
the spinning rate?



Let's attach a spring on the center of a flywheel disk. Then we attach another disk
into the other end of the spring. Then we press the disks together. The spring becomes
compressed. Then we tie this thing with a string. This thing we have constructed is a
flywheel. It's frictionless flywheel. Now we make the flywheel spin. At some moment
the sting breaks. What can we say about the spinning rate, when the string breaks?

 

Offline jartza

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« Reply #31 on: 15/11/2010 15:08:48 »
I think I elaborated a bit on it already.  No offense, but I find your posts to be a bit confusing (it may be a language issue?), which is why I haven't been able to answer them better.  Do you have a specific question about mass and energy and their relationship?


No I don't really have a question.
Would this be a tricky question for you:
Is the mass of relativistic gas the sum of rest masses of the particles?
Relativistic gas means very hot gas.
 

Offline JP

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« Reply #32 on: 16/11/2010 03:34:43 »
Generally, the answer would be no.  It would depend on what you wanted to do with "mass," but if you put the gas in a box and wanted to push the box, the apparent (inertial) mass of the box would be due to the rest/invariant masses of the particles plus a mass term resulting from the energies of the particles.
 

Offline jartza

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« Reply #33 on: 16/11/2010 08:13:06 »
Generally, the answer would be no.  It would depend on what you wanted to do with "mass," but if you put the gas in a box and wanted to push the box, the apparent (inertial) mass of the box would be due to the rest/invariant masses of the particles plus a mass term resulting from the energies of the particles.

So the real mass of the gas in the box is the sum of every particle's rest mass.

If we put some mass in a box, and half of the mass turns into energy, then the mass in the box is halved. There is simple logic in this.

My mass is 7 kg. Scientists have found out that mass of typical adult human being is about 7 kg. This  is still new and uncertain stuff. And silly laypeople think they know their mass, and with good accuracy.  ;D




 

Offline JP

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« Reply #34 on: 16/11/2010 09:03:22 »
Generally, the answer would be no.  It would depend on what you wanted to do with "mass," but if you put the gas in a box and wanted to push the box, the apparent (inertial) mass of the box would be due to the rest/invariant masses of the particles plus a mass term resulting from the energies of the particles.

So the real mass of the gas in the box is the sum of every particle's rest mass.
That's not what I said at all!.  You're describing one term, but the other term is from their kinetic energies, since this also contributes to the inertial mass of the box.  Using terms like "real mass" is confusing, since various ways of accounting for mass have very specific meanings, and they're all real.

Quote
If we put some mass in a box, and half of the mass turns into energy, then the mass in the box is halved. There is simple logic in this.
It depends how you count mass.  The inertial mass of the box, which is what most people would use to describe the mass of a box, stays the same.  For example, atoms have more mass than you would get by just summing the rest masses of all their fundamental particles.  This is because the energies associated with binding all these particles together also add to the inertial and gravitational mass of the atom. 

I think you're describing the science of this correctly, but you're trying to claim that this science means there's some sort of new conservation law or some kind of "real" mass, which is incorrect.
 

Offline jartza

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« Reply #35 on: 16/11/2010 09:55:05 »
I think you're describing the science of this correctly, but you're trying to claim that this science means there's some sort of new conservation law or some kind of "real" mass, which is incorrect.

The conservation of apparent mass is the thing that I mean. It's in Wikipedia. It's called conservation of mass there.


So when a flywheel is heated uniformly it's apparent moment of inertia increases an amount that is proportional to the apparent mass increase.



 

Offline JP

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« Reply #36 on: 16/11/2010 09:58:37 »
So what's new about the conservation law?  I agree that it exists, but it's well-known.
 

Offline jartza

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« Reply #37 on: 16/11/2010 10:14:23 »
It's not well known. It's new for you guys.
It might even be new. I don't know when it appeared into Wikipedia.
Should I have mentioned Wikipedia straight away?
 

Offline JP

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« Reply #38 on: 16/11/2010 10:30:38 »
It's not well known. It's new for you guys.
It might even be new. I don't know when it appeared into Wikipedia.
Should I have mentioned Wikipedia straight away?

How can I argue with you telling us what we know and don't know?  Anyway, I think the question is resolved.
 

Offline simplified

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« Reply #39 on: 19/11/2010 16:01:14 »
Nearby  Sirius B a photon is approaching to it, this photon is receiving energy. Is this event reducing mass of Sirius B?


Falling is a straightforward thing. No energy change happens.


Plasma inhabitants of Sirius B see increased frequency of photons from Sirius A. Frequency of these photons is increased in 1,00023 times.However they don't see increasing of energy of the photons.Then you should change the formula of photon energy.
                        :P
 

Offline simplified

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« Reply #40 on: 19/11/2010 16:04:00 »
Generally, the answer would be no.  It would depend on what you wanted to do with "mass," but if you put the gas in a box and wanted to push the box, the apparent (inertial) mass of the box would be due to the rest/invariant masses of the particles plus a mass term resulting from the energies of the particles.

So the real mass of the gas in the box is the sum of every particle's rest mass.

If we put some mass in a box, and half of the mass turns into energy, then the mass in the box is halved. There is simple logic in this.

My mass is 7 kg. Scientists have found out that mass of typical adult human being is about 7 kg. This  is still new and uncertain stuff. And silly laypeople think they know their mass, and with good accuracy.  ;D





Then you should change "G" :)
 

Offline jartza

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« Reply #41 on: 19/11/2010 17:29:09 »
Plasma inhabitants of Sirius B see increased frequency of photons from Sirius A. Frequency of these photons is increased in 1,00023 times.However they don't see increasing of energy of the photons.Then you should change the formula of photon energy.
                        :P


These plasma people fell into Sirius B, their energy or frequency did not
change when they where falling. When they crashed into the surface of the
star their energy and frequency decreased, and the energy and frequency of
the surface increased.

Now same story with photons:

When photons fall towards Sirius B their energy or frequency does not change.
When photons crash into the plasma beings, photon's energy and frequency decrease
to zero, and the energy and frequency of the plasma folks increases.



« Last Edit: 19/11/2010 17:43:00 by jartza »
 

Offline simplified

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« Reply #42 on: 19/11/2010 20:01:32 »
Then you should disprove this formula:
                    v = v_0 /√[1-2GM/Rc˛]
v-frequency        ::)
 

Offline jartza

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« Reply #43 on: 19/11/2010 20:59:50 »
Then you should disprove this formula:
                    v = v_0 /√[1-2GM/Rc˛]
v-frequency        ::)


When a photon whose frequency has not changed hits an observer whose frequency
has decreased, the observer says the frequency of the photon has increased.


Increase of frequency of a photon is a very silly idea.
Are new crests and troughs created? Well that's silly.
Does photon contract while holes between photons are created? That's silly too.

[Combined two posts & removed loads of unnecessary whitespace - Mod]
« Last Edit: 20/11/2010 11:05:00 by peppercorn »
 

Offline jartza

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« Reply #44 on: 02/12/2010 07:12:00 »
So where's the gratefulness? I'm trying to help you guys. :)


Here's an excerpt from Wikipedia:

In physics, mass–energy equivalence is the concept that the mass of a body is a measure of its energy content.


Now read that sentence five times, slowly. Then answer the question "are mass and energy equivalent"

 

Offline peppercorn

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« Reply #45 on: 02/12/2010 11:22:13 »
:D  Is this load of old drivel still going???
Well, good luck with that! ::)
 

Offline yor_on

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« Reply #46 on: 02/12/2010 15:03:08 »
I think Simplified is right in his description, The photon traveling toward Sirius are falling into a 'gravity well'. As seen from the 'frame' of A Sirian :) that photon indeed have increased its momentum and frequency becoming blue shifted as it according to the Sirian 'gains' energy through the 'gravity' bending the light.. The opposite happens to a photon climbing out from a gravity well where it instead becomes 'red shifted' as it 'expends energy'.

But that's all about frames of reference. You can also see it as the photon consists of some sort of 'Energy-quanta', and looked at this way the photon starts with, let's say three Eq (ahem:) and when free from the 'gravitational disturbance' it will be found to still have those three Eq, no matter if you measure it after 'climbing out' or 'falling in'.

What the observer sees is a relation connected to his 'frame of reference' and invalid in another 'frame of reference, for example the photon coasting next to our original photon 'at rest' with him will swear, if you asked him, that his pal never changed 'energy' or 'frequency'. As I see it :)
 

Offline jartza

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« Reply #47 on: 02/12/2010 15:53:27 »
Quite right, yor_on, particularly the part where photon's pal saw no change in the other photon was good.

BUT  ... there is a law of conservation of frequency.






Here we see two identical planets falling towards each other. While this falling is happening the frequency of the whole system stays F. And because of symmetry F1 stays the same as F2.

(F1 means frequency of schrodingen wave of planet F1)


 

« Last Edit: 03/12/2010 00:23:40 by jartza »
 

Offline jartza

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« Reply #48 on: 03/12/2010 03:21:56 »
:D  Is this load of old drivel still going???
Well, good luck with that! ::)


You are nasty.

 

Offline Bored chemist

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« Reply #49 on: 03/12/2010 08:34:05 »
:D  Is this load of old drivel still going???
Well, good luck with that! ::)


You are nasty.




I think that clear ad hom attack shows that this thread is going nowhere.
 

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