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Author Topic: Another chlorine conundrum  (Read 2868 times)

Offline Paul D

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Another chlorine conundrum
« on: 23/02/2006 11:21:09 »
If I react Iodine with sodium hypochlorite under alkaline conditions I get this reaction:
I2 + 7NaOCl + 6NaOH = 2Na3H2IO6 + 7NaCl + 2H2O

If I remove the sodium hydroxide I get chlorine why and what is the mechanism?
anybody any ideas



 

Offline Ray hinton

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Re: Another chlorine conundrum
« Reply #1 on: 23/02/2006 23:02:50 »
i had the idea of putting a frog in my little sisters bed.
 

Offline lightarrow

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Re: Another chlorine conundrum
« Reply #2 on: 15/08/2006 12:12:52 »
The reaction is: I2 + 2NaOH + 5NaClO  -->  2NaIO3 + 5NaCl + H2O.
You get chlorine simply from NaClO and NaCl when the solution is not alcaline: ClO- + Cl- + 2H+  -->  Cl2 + H2O
« Last Edit: 15/08/2006 12:24:18 by lightarrow »
 

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Re: Another chlorine conundrum
« Reply #2 on: 15/08/2006 12:12:52 »

 

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