No, just that heating quickly requires a higher energy input rate, you still ( assuming there are no losses or that they are very small compared to the input energy) have to supply a certain number of Joules of energy. If you apply for example 100000 joules (100 kilojoules, which is not the same as the joule in food BTW) in a period of 100 seconds, you have supplied energy at a rate of 1kW for 100 seconds, which would boil enough water to make a cup of tea very hot. If you apply at a rate of 0.5 kW, then the water will take 200 seconds to reach the same temperature. Conversely, if the rate is 5kW, the water will be hot in 20 seconds. This corresponds roughly with a kettle ( 1kW element), a microwave oven ( being around 500W applied to the cavity for a small one) or a gas or electric instant boiler respectively.