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Author Topic: need equation help  (Read 2601 times)

Offline jezza

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need equation help
« on: 18/05/2006 13:24:50 »
ok so i have to find the specific heat capacity of a metal.
the question says: draw a graph of time vs temp (which i have done) and from the equation E=mC calcuatle the specific heat capacity? and ideas?

the second part is i have to calculate the thermal conductivity of a metal rod using this formaular:  Q/t = A ((2 - 1)/X) i dont know if i have to rearange this, but i have to find (thermal conductivity) i think x is length of rod, theta1 - theta2 is the temp difference, A is the cross sectional area...sooo any ideas, im truly stumped


 

ROBERT

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Re: need equation help
« Reply #1 on: 18/05/2006 14:12:01 »
" The specific heat capacity (the symbol c or s, also called specific heat or SHC) of a substance is defined as heat capacity per unit mass. The SI unit for specific heat capacity is the joule per kilogram kelvin, Jkg-1K-1, which is the amount of energy required to raise the temperature of one kilogram of the substance by one kelvin. Heat capacity can be measured by using calorimetry."
http://en.wikipedia.org/wiki/Specific_heat_capacity

I hope this info is not for your "heated bicycle seat" , Jezza :).

« Last Edit: 18/05/2006 14:15:29 by ROBERT »
 

Offline jezza

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Re: need equation help
« Reply #2 on: 18/05/2006 17:11:15 »
quote:
Originally posted by ROBERT


I hope this info is not for your "heated bicycle seat" , Jezza :).



haha no, but that helps a bit thanks
 

Offline Soul Surfer

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Re: need equation help
« Reply #3 on: 20/05/2006 14:53:07 »
Jezza you have missed out a lot of important details of your experiment and I do not immediately recognise all the symbols used in your equation.  You need to give a lot more detail before it is possible to answer your questions fully.

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Offline jezza

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Re: need equation help
« Reply #4 on: 20/05/2006 17:56:04 »
yea it wasnt like that when i did it, umm is meant to be theta, and this , is lambda

oh yea and this , is delta
 

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Re: need equation help
« Reply #4 on: 20/05/2006 17:56:04 »

 

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