Naked Science Forum

Welcome, Guest. Please login or register.
Did you miss your activation email?
19/06/2013 13:07:44

Author Topic: How much does a brick and a half weigh?  (Read 1705 times)

pippystardust

  • Newbie
  • *
  • Posts: 15
    • View Profile
  • on: 02/04/2012 23:50:35
if a brick weighs 4pounds and half a brick
  then what does a brick and a half weigh ?
« Last Edit: 04/04/2012 22:22:38 by chris »

Joe L. Ogan

  • Sr. Member
  • ****
  • Posts: 459
    • View Profile
  • Reply #1 on: 03/04/2012 01:04:50
Is there something tricky about this.  I see your point  Thanks for comments,, joe L.Ogan
« Last Edit: 03/04/2012 14:06:43 by Joe L. Ogan »

CliffordK

  • Hero Member
  • *****
  • Posts: 4975
  • Site Moderator
    • View Profile
  • Reply #2 on: 03/04/2012 03:10:28
I think you're off a bit.
I'd put the answer at 12 pounds.

RD

  • Neilep Level Member
  • ******
  • Posts: 6375
    • View Profile
  • Reply #3 on: 03/04/2012 05:00:53
if a brick weighs 4pounds and half a brick
  then what does a brick and a half weigh ?

i.e.        b = 4 + ½b
=>     ½b = 4
=>        b = 8
=> CliffordK is correct
« Last Edit: 03/04/2012 05:02:49 by RD »

pippystardust

  • Newbie
  • *
  • Posts: 15
    • View Profile
  • Reply #4 on: 03/04/2012 12:12:55
  Well done Clifford    the answer is indeed 12 pounds     its a simple algebra question made tricky by its wording...   the question is basically    What is the weight of a the brick ?

This one has caused a helluva rumpus in work  even amongst academics ..its only when i DREW it on a board as a seesaw   with a brick on one side.. balanced by a half brick and a 4lb weight on the other that SOME people started to get it !!!!

damocles

  • Hero Member
  • *****
  • Posts: 723
    • View Profile
  • Reply #5 on: 03/04/2012 12:27:22
There was an old (probably first world war vintage) puzzle that went: "If a hen and a half laid an egg and a half in a day and a half, how many eggs would a rooster lay in a week?". That was, of course, the easy one. The harder variant went: "If a hen and a half laid an egg and a half in a day and a half, how many eggs would a hen (working at the same rate) lay in six days?"

imatfaal

  • Hero Member
  • *****
  • Posts: 2970
  • rouge moderator
    • View Profile
  • Reply #6 on: 03/04/2012 15:31:26
There was an old (probably first world war vintage) puzzle that went: "If a hen and a half laid an egg and a half in a day and a half, how many eggs would a rooster lay in a week?". That was, of course, the easy one. The harder variant went: "If a hen and a half laid an egg and a half in a day and a half, how many eggs would a hen (working at the same rate) lay in six days?"

Your second question - and PippySD's OP are important.  Algebra is great -  I love it - but it is of little use if you cannot take real world lumpen phrase and represent it algebraically

Don_1

  • Neilep Level Member
  • ******
  • Posts: 6119
  • A stupid comment for every occasion.
    • View Profile
    • Knight Light Haulage
  • Reply #7 on: 05/04/2012 14:14:37
Based on all of this, can you tell me then, how much milk is in a bar of Cadbury's Dairy Milk?

CliffordK

  • Hero Member
  • *****
  • Posts: 4975
  • Site Moderator
    • View Profile
  • Reply #8 on: 06/04/2012 04:02:28
There was an old (probably first world war vintage) puzzle that went: "If a hen and a half laid an egg and a half in a day and a half, how many eggs would a rooster lay in a week?". That was, of course, the easy one. The harder variant went: "If a hen and a half laid an egg and a half in a day and a half, how many eggs would a hen (working at the same rate) lay in six days?"

Hmmmm

So, the question is which half of the wishbone did the half a hen have.     :-\

So, algebraically, one gets...
R = the number of eggs laid by the rooster...
E = the number of eggs laid in 6 days.
H = the number of eggs that 1.5 hens lays in 1.5 d.
So, it would be

E =10xR + 4xH   :o

So...
One must conclude E=6  eggs laid by one hen in 6 days.  ::)

neilep

  • Withdrawnmist
  • Too Much Free Time Level Member
  • **********
  • Posts: 20564
    • View Profile
  • Reply #9 on: 20/08/2012 13:33:07
Based on all of this, can you tell me then, how much milk is in a bar of Cadbury's Dairy Milk?

As a firm believer in empirical study I took a bar of choccy and asked a cow !....The cow consumed the choccy and then did a cow pat !....so...I reckon it's about 2 litres !

*broken English mode* Cow eat wrapper too.....silly cow !!





Bona- fide non-doctored piccy of cow eaty choccy !





damocles

  • Hero Member
  • *****
  • Posts: 723
    • View Profile
  • Reply #10 on: 20/08/2012 13:49:36
From CliffordK:
Quote
So, algebraically, one gets...
R = the number of eggs laid by the rooster...
E = the number of eggs laid in 6 days.
H = the number of eggs that 1.5 hens lays in 1.5 d.
So, it would be

E =10xR + 4xH   

So...
One must conclude E=6  eggs laid by one hen in 6 days. 

so there are the Eggs and the Rooster, but the Rooster will lay 0  -- Rooster is the key, because when we cancel the lower case we arrive at
ERR0R
and we can conclude that the answer must be 4 eggs, not 6!

Bored chemist

  • Neilep Level Member
  • ******
  • Posts: 7244
    • View Profile
  • Reply #11 on: 20/08/2012 18:43:12
From CliffordK:
Quote
So, algebraically, one gets...
R = the number of eggs laid by the rooster...
E = the number of eggs laid in 6 days.
H = the number of eggs that 1.5 hens lays in 1.5 d.
So, it would be

E =10xR + 4xH   

So...
One must conclude E=6  eggs laid by one hen in 6 days. 

so there are the Eggs and the Rooster, but the Rooster will lay 0  -- Rooster is the key, because when we cancel the lower case we arrive at
ERR0R
and we can conclude that the answer must be 4 eggs, not 6!



Nobody said the answer  was 720

 

Naked Scientists Science Radio Show Home Who are The Naked Scientists Information about Naked Scientists
Naked Scientists Podcast Ask the Naked Scientists Podcast Question of the Week Podcast
Naked Science Articles Experiments to do at Home Science Discussion Forum
Science News Stories Answers to Science Questions Interviews with Famous Scientists

Information presented on this website is the opinion of the individual contributors and does not reflect the general views of the administrators, editors, moderators, sponsors, Cambridge University or the public at large.

Click here for the Naked Scientists PODCAST

The contents of this site are © The Naked Scientists® 2000-2013. The Naked Scientists® and Naked Science™ are registered trademarks.


Powered by MySQL Powered by PHP SMF 2.0 | SMF © 2011, Simple Machines Valid XHTML 1.0! Valid CSS!