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Author Topic: Does the wave function dictate no energy?  (Read 1585 times)

Offline Ęthelwulf

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Does the wave function dictate no energy?
« on: 05/04/2012 13:45:52 »
I have came to think that if the universe possesses a boundary, a condition seperating two realities then we may view the universe in a unique way. The boundary 9d5ed678fe57bcca610140957afab571.gif of a universe is given with a wave function as

289095b878e8e4a6029dbab4ef981f61.gif.

This is the approach that makes sense if the wave function is bound inside of the universe. In a similar approach then, the energy of the universe is defined by quantizing the Einstein equations

4cb70d51e4a3e3e02dafddfd5c45c1c6.gif

I speculate there is a unique similarity, that the wave function might be giving rise to zero energy and the universe is not what we encompass as a whole. My original equation, as small and simple as it is, stands true for particles in an enclosed system for that system to have walls, or a boundary.


 

Offline Ęthelwulf

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Re: Does the wave function dictate no energy?
« Reply #1 on: 05/04/2012 14:09:47 »
I could potentially see people saying ''but we are talking about energy inside the system, not the boundaries.''

Well, actually, according to black hole mechanics (and in many ways our universe is like a black hole, a theory which is being propogated by Sean Carrol), is that information of system can be fully described in the boundary.
 

Offline yor_on

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Re: Does the wave function dictate no energy?
« Reply #2 on: 30/05/2012 11:01:56 »
Your gif's doesn't show Wulf.

And you better flesh the idea out in some more words too. The wave functions reality and boundaries seems a question of some dispute.
==

Ops, the gif's not showing was my browsers fault.
But the rest stands.
« Last Edit: 31/05/2012 01:48:17 by yor_on »
 

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Re: Does the wave function dictate no energy?
« Reply #2 on: 30/05/2012 11:01:56 »

 

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