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Author Topic: What will happen if we increase power volt of the plasma ball ?  (Read 4118 times)

Offline taregg

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same question...
« Last Edit: 05/02/2013 23:31:03 by JP »


 

Offline taregg

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can any body answer my question..please
 

Offline CliffordK

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According to Wikipedia & Softpedia, the plasma balls typically run at 2000V to 5000V (they don't list the amps). 

However, that is enough power to cause serious burns, or it could even potentially be lethal.

More power would likely give one more sparks inside the ball.

However, as noted by placing your hand on the ball, what is happening inside and outside of the ball is not entirely isolated, and increasing the power by an order of magnitude might put one at risk of shock.

Also, keep in mind that the system is designed for a specific power rating.  At say, 10x the power rating, you might run the risk of burning out insulation that you hadn't intended.

And, of course, generating more radio interference. 

I presume there is a size/voltage relationship, so if you increase the size of the ball, you may need higher voltage.
 

Offline taregg

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what about if we dicrease the power . does it illuminated light
« Last Edit: 04/04/2013 02:55:38 by taregg »
 

Offline taregg

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please some body answer my question
 

Offline evan_au

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There are many factors which affect the behaviour of a plasma ball:
  • The gas mixture and pressure (which affects the colours)
  • The voltage (in Volts)
  • The frequency (in Hertz)
  • The resistance which limits the current
  • The capacitance of your hand on the glass
Assuming that you aren't planning to change the glass ball or the gas mixture:
  • Once the gas inside the ball becomes ionised, so it is almost a short circuit. If you run it at a high enough voltage and frequency, it will just become a spark inside the ball, which will eventually melt the electrode and the glass. This would probably take a continuous power of 1kW or more, at many MHz.
  • Without trying to melt anything, more current will flow, more power will be dissipated, and the light will be brighter if you:
  • Increase the voltage
  • Increase the capacitance
  • Increase the frequency
  • Decrease the resistance
Less light will be produced if you do the reverse.
If the voltage drops below the ionisation voltage of the gas mixture, the current immediately drops to virtually zero, and the light suddenly stops. 
 

Offline taregg

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 so it does mean...
.High volt = bright light.
.very high volt= blasma branch light.
.extreme volt= sparks.
(all this three types have the same pressure gas discharge and differents volt)
is it correct..?
« Last Edit: 05/04/2013 05:36:27 by taregg »
 

Offline taregg

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is there some body can answer me please...
 

Offline evan_au

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Yes, that's the general trend...
 

Offline gammaworld1

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It would burn out as the transformer doesn't have enough space between the winds for the increased volts. Too much and you would exceed the capacitor which means it will spark, sputter and then go out forever.

But, assuming it didn't or if you didn't increase it by too much or if you completely gutted it so it would work with truly high amp/volts it would light up very brightly. With enough current (amps) I would consider wearing sunscreen and wearing shades. The argon/neon should act as a blanket to most ionizing radiation. In a compete vacuum, however, those radiations become a serious problem.

In the end, a lot more amps means the gas inside will get hot and the glass bulb itself will eventually melt.
A lot more volts, the more disruptive and blinding "sparks"/plasma. At some point it will even spark outside the chamber.
A lot more power overall will shatter the bulb. The plasma sparks would sound like lightning inside the bulb and eventually the 'thunder' would shatter the plasma bulb.

 

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