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Author Topic: Is NH[sub]4[/sub]OH present in the vapor?  (Read 1791 times)

Offline Atomic-S

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Is NH[sub]4[/sub]OH present in the vapor?
« on: 19/03/2013 01:26:06 »
In a partly-filled closed container of aqueous ammonia, is NH4OH as such a component of the vapor phase, and if so, what fraction of the vapor phase consists of it?


 

Offline lightarrow

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Re: Is NH[sub]4[/sub]OH present in the vapor?
« Reply #1 on: 19/03/2013 18:35:32 »
OH- is a too strong base to coexist even with the weak acid NH4+ so it's very unprobable it can form a significative amount of NH4OH, even in the gas phase.
There surely is, but it's certainly high unstable, so it's difficult to compute how much there can be (unless with experimental technics as laser/maser spectroscopy).
« Last Edit: 19/03/2013 18:38:19 by lightarrow »
 

Offline damocles

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Re: Is NH[sub]4[/sub]OH present in the vapor?
« Reply #2 on: 11/04/2013 00:00:42 »
OH- is a too strong base to coexist even with the weak acid NH4+ so it's very unprobable it can form a significative amount of NH4OH, even in the gas phase.
There surely is, but it's certainly high unstable, so it's difficult to compute how much there can be (unless with experimental technics as laser/maser spectroscopy).

On the other hand NH3 and H2O have a great affinity for each other, and there would certainly be quite a significant amount of NH3.H2O in the vapour -- perhaps even a majority of the vapour would have this composition. It would depend very much on the temperature and the concentration of the ammonia in the water. So while NH4+OH is not a possibility, NH3.H2O is a very real possibility.
 

Offline lightarrow

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Re: Is NH[sub]4[/sub]OH present in the vapor?
« Reply #3 on: 12/04/2013 10:57:44 »
Of course. But I assumed the OP didn't mean NH3.H2O because of its statement "NH4OH as such".
 

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Re: Is NH[sub]4[/sub]OH present in the vapor?
« Reply #3 on: 12/04/2013 10:57:44 »

 

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