# The Naked Scientists Forum

### Author Topic: The common distance of the stars  (Read 1264 times)

#### aetzbar

• Jr. Member
• Posts: 30
##### The common distance of the stars
« on: 18/03/2015 17:52:31 »
The common distance of the stars , by Aetzbar ..1

Countlees  stars moving infinite space.
The stars are combined according to the idea of a central star , and ather stars revolving
around it. Each star is a central star and ather star, at the same time.

Kepler discovered the univerce formula  D^3 : T^2 = P      ( P is number )
D  The distance of ather star from central star.
T  Time that ather star rotates around a central star.

Newton : Each star has its material quantity ( M  view Newton)
M determines  P that appesrs in Kepler's universe formula.
If M will increase 5 times,then  either P increase 5 times.

How to get the P of earth ?    with Kepler's universe formula.   D^3 : T^2 = P
The earth is a central star for the moon.
Moon is far from earth 384000 km, and time it orbited the earth 672 hours.
P = 384000^3 : 672^2 = 1.25*10^11
P of earth is determined by M of earth.

There are an infinite number of combination of D  and  T ,if selected D ,the formula tell us T.      If you want to send a satellite to earth, a height of  88000 km ,time it will circle the earth,
predetermined.     T = root of ( 88000^3 : 1.25*10^11) = 74 hours

Finding p of the Sun.
The Sun is a central star for the earth (with the moon moves around)
P is obtained by the distance ( Earth  Sun) and time of 1 year in hours.
P of Sun = 429*10^14    P of the Sun determined by M of the Sun.
The common distance of the stars , by Aetzbar ..2

Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a
Tunnel  that reaches the other side of the earth. This ball will illustrate a pendulum
Movement , between the two openings of the tunnel.
The cycle time will be 1.4 hours.   Marked  ]T[
P of earth and  ]T[ of  earth ,determines  by M of earth.

The common distance of the stars
As we move away from a star, lap time around it will grow. ( T increases)  Therefore ,the
Equality   T =  ]T[   must appear each star, at some distance from the center of the star.
So that all the stars in the universe will be in harmony, need only a single distance   which  appears the equality  T =  ]T[

How do we find the common distance of the stars ?
Since M of star determines its  P and  ]T[ , must be a connection between P and  ]T[
The connection is  P* ]T[^2 = number
This connection will reveal the common distance of the stars.
P of earth = 1.3*10^11  and   ]T[ of earth = 1.4 hours
1.3 * 10^11)*1.4^2 = 2.5 * 10^11                                                                                                         )
( D^3 : T^2) * [T[^2 = 2.5 * 10^11
T = ]T[
D^3 = 2.5*10^11
D = 6300 kilometers
The common distance of the stars  = 6300 km
Satellite close to the ground, makes a complete revolution in 1.4 hours.
]T[ of earth is 1.4 hours.
Earth space are within 6300 km from the center of the earth.
The common distance of the stars , by Aetzbar ..3

6300 km is a Natural Physical Constant.
The equality of times  T =  ]T[  appears  at  6300 km from the center of each star.
Each star has its unique M and unique  ]T[
M*  ]T[^2 = constant
We live in a place of equality times

]T[ of Sun is 8.7 seconds
In distance of 6300 km from the center of the Sun, T is 8.7 seconds
]T[ of Earth is 5050 seconds
In distance of 6300 km from the center of the Earth, T is 5050 seconds
6300 km is common distance of all stars

#### aetzbar

• Jr. Member
• Posts: 30
##### Re: The common distance of the stars
« Reply #1 on: 20/03/2015 12:09:08 »
5 steps Creating a dynamic universe.

First step: Each star is moving and never rests.
Second step: Each star is a central star and side star, at the same time.

The Sun is a central star for the Earth ,and Earth is a central star for the Moon.
The Earth is a side star for the Sun, and the Moon is a side star for the Earth.
Side star revolves around central stare, with lap time T.

Third step: Each star has mass  M and  Cycle time  ]T[
Fourth step: M determines  ]T[ by the formula  M* ]T[^2 = constant
Fifth step: The equality. Lap time = Cycle time .( or  ]T[ =  T ) will appear at
D= 6300 km, from the center of each star.(6300 km is a Natural Physical Constant)

Thus we have obtained the known universe.
Each star has a unique P resulting from the formula D^3 : T^2

#### aetzbar

• Jr. Member
• Posts: 30
##### Re: The common distance of the stars
« Reply #2 on: 21/03/2015 14:26:55 »
Dynamic universe without gravity, by Aetzbar --------------------------------------------------1   .
Each star has its Material quantity ( M  Newtonian view)
The stars are moving and never stop.
Stars move like a screw  turn and advanced.

Each star is a central star and side star, at the same time.(Copernican view)
The Sun is a central star for the Earth ,and Earth is a central star for the Moon.
The Earth is a side star for the Sun, and the Moon is a side star for the Earth.
Side star revolves around central stare, with lap time T

Let's say that the sun is a point and earth as a point
If we move away from the sun,the distance D will increase from zero km to infinity km
lap time T will increase (from zero hours  to infinity hours)
If we move  away from the Earth,( D will increase from zero km to infinity km )
lap time T will increase (from zero hours to infinity hours)

The Sun has a unique fit between D and T, and the Earth has a unique fit of D and T.
Each star has its unique fit between D and T.

Kepler fined the formula of the stars  D^3 : T^2 = P
P is a unique number of star, that represents a unique fit between D and T.

There is a link between M of star to P of star  ( M1 : M2 = P1 : P2  )

How to get the P of earth ?
The earth is a central star for the moon.
Moon is far from earth D =  384000 km, and time it orbited the earth T = 672 hours.
P of Earth = 384000^3 : 672^2 = 1.25*10^11
Dynamic universe without gravity, by Aetzbar ------------------------------------------------ 2
Finding p of the Sun.
The Sun is a central star for the earth (with the moon moves around)
P is obtained by the distance ( Earth  Sun) and time of 1 year in hours.
P of Sun = 429*10^14

Each star has also  its Cycle time ( marked  ]T[ )
Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a
Tunnel  that reaches the other side of the earth. This ball will illustrated a pendulum
Movement ( of  1.4 hours ) between the two openings of the tunnel.
The cycle time of the Earth will be 1.4 hours.
each star has its Cycle time.

M of star  determines its  ]T[ , by the formula  M* ]T[^2 = K (constant)
Because  M1 : M2 = P1 : P2
We have the formula P* ]T[^2 = K
According to P of Earth and  ]T[ of Earth , K = 2.5*10^11
With the formula  P* ]T[^2 = 2.5 *10^11 can calculate ]T[ of Sun = 8.7 seconds

Natural Physical Constant
The formula  P* ]T[^2 = 2.5*10^11
is the formula  (D^3 : T^2)* ]T[^2 = 2.5 * 10^11
The formula shows that the situation of  T = ]T[  appears at the distance of 6300 km, from
the center of each star.
D^3 = 2.5*10^11
D = 6300 km
Thererfor , 6300 km is a Natural Physical Constant.

Dynamic universe without gravity, by Aetzbar ------------------------------------------------ 3

The equality of times law
The equality. Lap time = Cycle time .( or  ]T[ =  T ) will appear only  at
D= 6300 km, from the center of each star.
6300 km is a Natural Physical Constant.
The equality of times law determines that each star has a unique fit between D and T

#### The Naked Scientists Forum

##### Re: The common distance of the stars
« Reply #2 on: 21/03/2015 14:26:55 »