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Author Topic: I need some help with my theory please.  (Read 1359 times)

Offline Thebox

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I need some help with my theory please.
« on: 18/11/2015 17:39:21 »
Most of you know my poker theory , I have it down to this model,




Is this understood? if not how can I improve it?  what maths do  I need?

i am trying to show this


https://en.wikipedia.org/wiki/Multivalued_function







« Last Edit: 18/11/2015 18:03:43 by Thebox »


 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #1 on: 19/11/2015 01:08:20 »
added diagram to show what I am trying to get at.

 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #2 on: 19/11/2015 13:33:04 »
added maths to represent the diagram


X^=Y={σ(x)/Y}/σ(z)/t

P(x^)/y/z=0_1/t

Y=∭(x}
 

Offline alancalverd

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Re: I need some help with my theory please.
« Reply #3 on: 19/11/2015 13:41:46 »
pi∫∫le
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #4 on: 19/11/2015 23:14:39 »
pi∫∫le

Only because you do not recognise this as maths you already know, you don't know this maths because it does not exist yet.  So you can't recognise it instantly. 

It reads elegantly.


x is constant

y and z are variable

x=52

y=104
« Last Edit: 19/11/2015 23:23:04 by Thebox »
 

Offline chiralSPO

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Re: I need some help with my theory please.
« Reply #5 on: 20/11/2015 00:40:32 »
It reads elegantly.


x is constant

y and z are variable

x=52

y=104

how is y a variable and 104?
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #6 on: 20/11/2015 08:39:58 »
It reads elegantly.


x is constant

y and z are variable

x=52

y=104

how is y a variable and 104?

X^  is x to the power of 2

which is equal to Y.   


X=Y


X only contains a specific 1 of 1/52  where Y contains 2 or more of a specific


If we have 100 decks of cards we have 100 chances that the top card is 1/52 to a specific card, all 100 top cards could be the same specific card, or all 100 top cards could contain no specific of the card. 


It is a variable compared to 1/52

X is rows and Y is columns, X can only have 1 out of 52 where y can have several of 1 of 52


X^=Y={σ(x)/Y}/σ(z)/t

P(x^)/y/z=0_1/t


X to the power of 2 is equal to y which is equal to a variation of x divided by Y which is distributed to multiple Z that is ever changing over time

so it cant be 1/52 because the 1 could be several or none. so the P=0_1/t
« Last Edit: 20/11/2015 08:43:15 by Thebox »
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #7 on: 20/11/2015 23:55:24 »
added -



we have a 1/36 chance of intercepting a 4/52 chance
« Last Edit: 21/11/2015 00:01:09 by Thebox »
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #8 on: 22/11/2015 16:01:23 »
1.6% chance there is no aces based on a 52 value wheel

4/52

{x}Δ{σX}={Y}=Δ4=σP[A]/{Y}

(ε, δ)=4/X

(ε, δ)=52/Y
« Last Edit: 22/11/2015 20:23:55 by Thebox »
 

Offline alancalverd

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Re: I need some help with my theory please.
« Reply #9 on: 23/11/2015 00:52:07 »
we have a 1/36 chance of intercepting a 4/52 chance
Wrong. It doesn't matter where the ball stops, or how many packs there are: the probability of any position being an ace is exactly the same, i.e. 1/13.

Take a simpler example. Toss a coin as many times as you like. The probability of the nth toss being a head is 1/2 whatever the value of n.
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #10 on: 23/11/2015 16:29:50 »
we have a 1/36 chance of intercepting a 4/52 chance
Wrong. It doesn't matter where the ball stops, or how many packs there are: the probability of any position being an ace is exactly the same, i.e. 1/13.

Take a simpler example. Toss a coin as many times as you like. The probability of the nth toss being a head is 1/2 whatever the value of n.

No Alan, honestly mate

φ{X}/t=1/52
Z



φ{Y}/t=0_52/52
^Z

∑{Y}≠∑{X}
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #11 on: 24/11/2015 00:44:07 »
added - surely this is understandable?

φ{X}=1:52

φ{Y1.....Y52}=(<1.=1.>1):52
 

Offline chiralSPO

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Re: I need some help with my theory please.
« Reply #12 on: 24/11/2015 02:05:24 »
added - surely this is understandable?

φ{X}=1:52

φ{Y1.....Y52}=(<1.=1.>1):52

nope. I might understand the first line, but I have no clue what the second line means...

typically = means "equal to" as in a = b means a is equal to b
and > means "greater than" as in c > d means c is greater than d
and < means "less than" as in d < c means d is less than c
(if c > d then d < c; if a = b then b = a)

by these definitions "<1.=1.>1" is completely nonsensical.

if you are not using standard, generally accepted notation, then you must explain what it is that you mean (at the very least define your operations)
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #13 on: 24/11/2015 09:27:26 »
added - surely this is understandable?

φ{X}=1:52

φ{Y1.....Y52}=(<1.=1.>1):52

nope. I might understand the first line, but I have no clue what the second line means...

typically = means "equal to" as in a = b means a is equal to b
and > means "greater than" as in c > d means c is greater than d
and < means "less than" as in d < c means d is less than c
(if c > d then d < c; if a = b then b = a)

by these definitions "<1.=1.>1" is completely nonsensical.

if you are not using standard, generally accepted notation, then you must explain what it is that you mean (at the very least define your operations)

Yes greater than and less than and equal to, I have put . to represent and/or.   And put it in brackets to rep a set

Help me please, I am trying to create something like this P(a ≤ x ≤ b) = ∫ f (x) dx to rep Y change.
« Last Edit: 24/11/2015 10:00:40 by Thebox »
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #14 on: 24/11/2015 10:16:02 »
X=52*52=X,Y

φ{X}=1:52

φ{Y1...............Y52}=?/52





This

ppp123,
ppp231,
ppp231,
ppp213


123,
231,
231,
213
ppp
ppp
ppp
ppp



spot the difference competition.
« Last Edit: 24/11/2015 11:11:23 by Thebox »
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #15 on: 25/11/2015 10:53:53 »
I have it simplified for you all.

draw card 1 from deck 1, a 1/52 to be any value

draw card 1 from deck 2, a 1/52 to be any value



1/52=1/52


Both cards have equal chance to being the same value.
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #16 on: 01/12/2015 03:45:08 »
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #17 on: 02/12/2015 17:56:40 »
Thank you A.

''In statistics, the autocorrelation of a random process describes the correlation between values of the process at different times, as a function of the two times or of the time lag. Let X be some repeatable process, and i be some point in time after the start of that process. (i may be an integer for a discrete-time process or a real number for a continuous-time process.) Then Xi is the value (or realization) produced by a given run of the process at time i. Suppose that the process is further known to have defined values for mean μi and variance σi2 for all times i. Then the definition of the autocorrelation between times s and t is''

I am trying to explain this .
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #18 on: 03/12/2015 14:50:51 »
This must be close?

λ(X)=φt

λ(Y)=σe4759d6009348c53a7ec5b37f2311f8f.gif/c437fa744de24ee33621872064351a35.gif


λ(X)=φt1=ab0294b94eb253246e368db2032b6e2e.gif

λ(Y)=σab0294b94eb253246e368db2032b6e2e.gif=t2

« Last Edit: 03/12/2015 14:54:30 by Thebox »
 

Offline Thebox

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Re: I need some help with my theory please.
« Reply #19 on: 03/12/2015 15:32:03 »
b47a6c1ed37ddfd8b43cffb07ec8da50.gif=f264c23330168e1922bc5572f7ccde6d.gif=b0a82aeebbb0efe2ad3c2aa2578287e9.gif


f0124548ee828be7cd09dc7c46b87049.gif=c11085258b39a399c1f25401bc214f46.gif=493b3090da0d63ad6bd4363d54e9bc1c.gif=e1e4561c09f001a29aa8216704c18d52.gif
 

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Re: I need some help with my theory please.
« Reply #19 on: 03/12/2015 15:32:03 »

 

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