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Author Topic: Do we account for acceleration in Gravitational time dilation?  (Read 418 times)

Offline Thebox

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Object (A) at ground state has zero velocity v=0.

object (A) at ground state has 9.82m/s of acceleration always, this is true or we would have no weight.


1 second of the Caesium clock is equal to ground state is equal to the weight and acceleration,


a golden constant ratio.



Do we account for this?

φ=(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)

Δφ=σ(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)



Clock (a)   at ground state on earth

clock (b)  at ground state on a sister earth 1000000 Ly away


M1=M2 in every detail including rotational speed and mass


Clock (a) is always in the present


clock  (b) is always in the present

X1
X2
y'=σ
t'=σφ

« Last Edit: 30/11/2015 13:09:18 by Thebox »


 

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