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I need to explain what would occur when the following substances are electrolysed:

molten Kbr
molten Al(2)O(3)
Nal solution
dilute sulphuric acid

i know they split, one goes to anode, one to cathode but i think one or two of them leave a substance free.......any help would be welcome

Many thanks

Hi J9sully!

Correct me if i'm wrong but i think this is what KBr would do:

Potassium has a valency of +1 so it goes to the negative electrode (cathode), the bromine would go to the other.

The aluminium has a +3 Valency so would go to the Cathode and the oxygen would go to the anode.

The Nal I assume means NaCl
Sodium has a valency of +1 so would go to the Cathode and The chlorine would go to anode

That's all I'm sure and it's been a while since I did this so if anyone knows better please feel free to point it out!

I Love Caesium!!!

About dilute sulphiric acid, on Cathode would develop hydrogen, on Anode xygen

Thanking you both for your very valuable all makes complete sense and has done me a huge favour....thanks again!!!


I think depend on the electrodes you use the product formed might be different. Like with O2 moves toward the anode, if anode is made of carbon, then CO2 will be produced. Or I could be just talking ____ here



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