How long do you have to accelerate at G to reach the speed of light?

25 May 2013

Question

Dear Dr Chris.

I have plucked up the courage to write to you with a question from a colleague of mine which I can't answer.

I have no idea why he wants to know this ( I think he reads too many science fiction comics or watches too much 'Star Treck' ) but here goes :-

If an object of negligible size & mass is launched from a standing start in a vacuum, and is subjected to an acceleration force of 1 G - how long will it take to reach the speed of light.

Hope you are able to provide an answer, or even a formula to calculate an approximate result when and if you have the time.

Best Regards

Jack Stott BSc(Hon) Elec Eng Science

Comments

It may be physics 101 but that's the wrong formula. That formula would be for constant velocity. The question was about constant
Acceleration which is meters per second squared or an increase of meters per second every second. So after the first second you going 10 meters per second after the second you're going 20 meters per second the third you're going 30 meters per second.

Well, id say if you assume that you can reach the speed of light by normal means and can achieve exactly 1g throughout the trip (I will use 300,000,000 m/s and 10m/s per second as rough approximations for this and assume this is from not moving at all) it would take approximately 30,000,000 seconds (500,000 minutes, 8333.33333333 hours, 347.222222222 days, 49.6031746032 weeks or 0.9539072039 years).

Thanks for the suggested answer, but the original poster did ask for the formula / workings...

its phys 101. Using only newtonian physics, v = v(0)+ gt; and v(0)=0
if we starts from rest:
t = v/g = 300,000,000/10 = 30,000,000s

Add a comment