Naked Science Forum
Non Life Sciences => Physics, Astronomy & Cosmology => Topic started by: guest39538 on 30/11/2015 12:57:50
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Object (A) at ground state has zero velocity v=0.
object (A) at ground state has 9.82m/s of acceleration always, this is true or we would have no weight.
1 second of the Caesium clock is equal to ground state is equal to the weight and acceleration,
a golden constant ratio.
Do we account for this?
φ=(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)
Δφ=σ²(1 second = 9,192, 631,770 cycles of the standard Cs-133 transition=a9.82m/s=(F=ma)=Newtons)
Clock (a) at ground state on earth
clock (b) at ground state on a sister earth 1000000 Ly away
M1=M2 in every detail including rotational speed and mass
Clock (a) is always in the present
clock (b) is always in the present
X1=φ
X2=φ
y'=σ²
t'=σ²φ