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Can someone summarise what tidal resonance theory is?
In miniature this can be imagined as follows. If you move your hands back and forth in the bathroom with water, you can create a mini-tsunami effortlessly and in seconds. The tidal wave is formed by a similar principle.
If you're talking about a spinning object, spinning stably on a point, we're looking at a ballerina, right?Putting this in the context of a 2/3rds liquid surface planet, what are those liquid arms doing with the gravitational pull of the Moon to stay stable?A flywheel, a counterweight, that other tide facing away from the Moon, right?
we're looking at a ballerina, right?
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That´s why bigger high tides always occur app. at 2:00 A.M. and at 2:00 P.M., because a "primary" bulge and the antipode one related to the other celestial body occur on same meridian and high tides add up.
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Interesting.A post that is written by someone who repeatedly posts nonsense and is completely wrong,earns a thank you from the guy who marked his own completely wrong response to his wrong-headed thread as the "best".It's time this site started to ban people who post anti-science.
Do you think your "resonance" idea is going to catch?
Why high tides from resonance are not formed in the south of the Gulf of Maine.
1. Why the "Lunar tidal current" crashing into the east shore of the Gulf of Maine does not create anomalously high tides in the south of the gulf, at least five meters high, the south of the bay is three times closer than the Bay of Fundy.2. The frontal collision of the "Lunar tidal current" falls on the eastern shore of the Gulf of Maine, why there are not formed thirty-meter tides, although the wedge-shaped bays and bays in the east of the Gulf of Men are quite numerous?
The lunar theory of tides is based on:1. On the blind faith of people, on the printed word.2. People do not want to think for themselves.
Interesting that the moon and the sun are not aligned in orbit (*) , the sun has a gravitational affect on the oceans so will cause a slight deform on the ocean , the moon as we know has a much larger affect on deforming the oceans and creating a tidal bulge (**).
You claim that a current of 15km/h is required in the Northern part of the Gulf of Maine, but buoy data from this area shows a maximum of 2.34km/h over the first 5 months of this year.
Quote from: Colin2B on 25/05/2018 05:06:06You claim that a current of 15km/h is required in the Northern part of the Gulf of Maine, but buoy data from this area shows a maximum of 2.34km/h over the first 5 months of this year.At a maximum of 2.34 km / h, what is the height of the tides?Find the height of the tides of 15 meters, the speed should be 15 km / h?If this does not happen, I will apologize to everyone for losing my time and yours.
Yesterday the Fundy tide was 11m and the buoy in N Gulf of Maine registered 1.98km/h
The length of the tidal wave depends on the diameter of the whirlpool.
Who is going to say that the shape of the rivers and estuaries makes the moon magically manifest with the tides?
It will be difficult to determine the amplitude of the tides with the help of the formula.It is easier to define it by experience.
Table of the amplitude of the tides of the Bay of Fundy:1 km / h - 5 m2 km / h - 10 m3 km / h - 15 m4 km / h - 20 m
A = V1 • V2 / twhere: A is the amplitude of the tidal wave (precession angle).V1 - rotation speed of the whirlpool.V2 is the orbital velocity of the Earth.t - the time of tilting of the whirlpool (12 hours).