The Naked Scientists
Toggle navigation
Login
Register
Podcasts
The Naked Scientists
eLife
Naked Genetics
Naked Astronomy
In short
Naked Neuroscience
Ask! The Naked Scientists
Question of the Week
Archive
Video
SUBSCRIBE to our Podcasts
Articles
Science News
Features
Interviews
Answers to Science Questions
Get Naked
Donate
Do an Experiment
Science Forum
Ask a Question
About
Meet the team
Our Sponsors
Site Map
Contact us
User menu
Login
Register
Search
Home
Help
Search
Tags
Member Map
Recent Topics
Login
Register
Naked Science Forum
On the Lighter Side
New Theories
What is the lowest quantum of energy in a gravitational wave?
« previous
next »
Print
Pages: [
1
]
Go Down
What is the lowest quantum of energy in a gravitational wave?
0 Replies
1754 Views
0 Tags
0 Members and 1 Guest are viewing this topic.
jerrygg38
(OP)
Naked Science Forum King!
1033
Activity:
0%
Thanked: 34 times
What is the lowest quantum of energy in a gravitational wave?
«
on:
22/07/2016 14:24:39 »
What is the lowest quantum of energy in a gravitational wave?
Gravitational waves are spherical waves which originate in the radiation of the protons bipolar energy. The component of all material existence is the dot-wave which has an equivalent mass of 1.566E-72Kg and a charge of 2.755E-61 coulombs as per Dot-wave theory calculations. Everything radiates dot-waves and the radiation pushes against former radiated dot-waves and this expands the universe but at the same time the backpressure produces gravity. Thus gravity is both positive, causing things to be pushed together and negative causing things to expand.
The dot-wave radiation is thus constrained. The protons cannot radiate all their dot-waves all at once because the entire universe is pushing back upon the protons. There most likely is another obstacle. Since the dot-waves do not radiate axially, the ability of a single dot-wave to leave the proton or groups of protons is limited by the spacing of the gravitational waves. The minimum spacing of the gravitational waves would equal the Plank distance.
Thus we have a barrier which must be crossed in order for groups of dot-waves to escape matter. The Plank length is 1.616E-35 meters. The equivalent rest mass for a photon of this wavelength is
Mg = h/(PL C^3) = (6.626E-34)/(1.616E-35) 2.694E25 = 1.523E-24Kg
The mass of a proton is 1.6726E-27kg so the mass necessary to radiate into the gravitational wave is equivalent to
#protons = Mp/Mg = 908.9 protons.
Since the mass/energy required for a gravitational wave to jump the Plank distance, an individual proton is quite stable and cannot radiate all its energy away. It takes groups of 909 protons to have the energy necessary to produce a quantum of a gravitational wave. Thus each proton within the Earth contributes a little dot-wave energy to produce the energy necessary for the gravitational wave.
Each individual proton loses a little energy and the radiation of proton energy depends on the ability of the combined dot-wave patterns to match up to produce a single gravitational spherical photon. So the radiation depends upon the universe pushing back upon the proton and at the same time the ability of groups of protons to produce dot-wave patterns which can produce a single gravitational wave. Thus there is a probability of events to produce a perfect combined dot-wave pattern so that the energy can escape the protons.
This calculation was performed on 7/22/16 and will require further checking and study by me.
Logged
Print
Pages: [
1
]
Go Up
« previous
next »
Tags:
There was an error while thanking
Thanking...