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It is possible to interpret this experiment with the Light coordinate system method
very-elemental units
Such an ether ether could not interact with the light.
Bored chemist:Mainly, my post was using the term "elemental," to mean the first, and presumably, the most-minuscule energy units. (I admit having used a redundant word. "very," there.)But the point I make is theoretically valid. If an ether exists and is composed of energy units, the units would certainly be more rarified than sub-quantal photons, If the ether is composed of units, in that respect similar to quantum systems, the ether's units could well be the first, and smallest, units in a march toward quantum systems. The smallest ether units, being much smaller than the photons are,then Michelson and Morley (who in their time were not yet even aware of the existence of photons) formulated their assumptions leaving out this possibility. Therefore, Michelson-Morley and its successors are not a disproof of ether.
he ether was invented specifically the be the medium that light travels through. Light not interacting with the ether would be like sound not interacting with air.
The whole ****ing point of the ether- or, to give it its full name, the "luminiferous ether" (i.e. the ether that carries light) is that it must interact with photons.
My point is simple. But it is not nonsensical. If an ether exists which happens to be mainly composed of vanishingly-tiny energy units, while the light beams that were measured in Michelson-Morley are composed of photon units which are much, much, larger, there cannot be an inertial interface between the light beams and the ether. Therefore, the ether cannot interact with the light beams. Michelson-Morley cannot disprove the existence of such an ether. Therefore, Michelson-Morley, and all its successors, based on the same kind of approach, do not disprove ether.
What you have said is that the MM experiment wouldn't detect the ether if the ether wasn't the ether.