# Naked Science Forum

## On the Lighter Side => New Theories => Topic started by: zyh on 21/05/2008 02:18:03

Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 21/05/2008 02:18:03
Mercury precession of the experiment: [do not have to spend money, a quarter of an hour to complete]
A simple experiment. For a line, 50 cm long; fixed line side a small steel ball, which is pendulum. Handheld pendulum top, top-down, the ball straight for the campaign. Hand slightly forced counterclockwise rotation, so that the ball trajectories for the oval. Hand forced to stop static, elliptical trajectory of the ball. Hand slightly forced counterclockwise rotation, can be seen in the anti-clockwise oval precession, That is,  the long axis of the ellipse around  a focus  anti-clockwise rotation; And vice versa, such as hand slightly forced clockwise rotation, Oval can be seen in the clockwise precession, that is, in the long axis of the ellipse around a focus  clockwise rotation.
Personally seen: elliptical orbit precession; personally by the flu: the orbit precession reason is force. Newton's gravity to run for the elliptical orbit of Mercury, a vortex of the sun's rotation, As the rotation speed of Mercury's rotation velocity slower than the sun, the Mercury orbit by the vortex of the role of precession. [Newton's theory of deviation]
Quantitative calculation: [High School]
Basic data: from the Mercury, d = 0.58 × 10 ^ 11m, the quality of the sun Ms = 1.98 × 10 ^ 30kg, the sun's rotation velocity ω s = 4.64 × 10 ^-7rod / s. solar rotation cycle t = 25day ., Eccentricity of e = 0.2
Mercury tangential acceleration at =--- qK ω sMsG / d ^ 2 ----------------. ①
Angular velocity difference: q = 1-25/88 = 0.715
Admission average: at-= 1 / π ∫ 0 → π (at × cos ω td ω t )...... ②
-= (2 / π) at
Mercury moving into a cycle angle d θ; d θ = (1 / 2) at-× t ^ 2 × 360 / 2 π d(1-e ^ 2) ------------- ③
Into the data: d θ =[ 2 × 0.716 × 0.40 × 4.64 × 10 ^ 7 × 1.98 × 10 ^ 30 × 6.67 × 10 ^- 11 × (25 × 24 × 3600) ^ 2 × 360] / [2 × 2 π ^ 2 × (0.581 × 0 ^ 11) ^ 3× (1-0.2 ^ 2) ]
=  7.98 × 10 ^ -6 degrees.
100-year cycle of 1460, the century precession 1.165 × 10 ^ -2 degrees (42 angle seconds);   This result and the actual value  are more identical.
Title: The most simple and reasonable solution about mercury precession
Post by: Soul Surfer on 21/05/2008 08:28:20
You cannot work it out that way Zyh Your "experiment" is totally irrelevant and your calculations to me look like a load of rubbish. Any effect of the sun's rotation on the orbit of mercury (which could exist due to gravitomagnetic frame dragging.)is indescribably smaller than what you suggest.

The relatavistic precession of the orbit of mercury is a tiny deviation in addition to the "normal" precession of the orbit of mercury due to the influence of the other planets.

There is currently an extremely precise bit of engineering orbiting the earth to measure the gravitomagnetc frame dragging due to the rotation of the earth that is just producing results.

It annoys me how you loonies try to put up  and publicise pseudo scientific claptrap on the basis that most people won't understand it anyway and it makes you look good.  I assure you that you are just added to the line of loonies that we suffer.  This topic should really be deleted or at best transferred to the "new theories" area with most of zyh's contributions to these pages
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 27/05/2008 01:48:49
Mercury precession (Newton's theory deviation of: 43 angle seconds per century )
1． Kepler's idea of the same gravity as the car spoke, on the one hand to maintain the planets in their orbits can not run away (ie the components), on the other hand, with the sun's rotation around the sun forced planetary rotation (that is tangential component) . I use Cavendish torsion balance has been measured rotating the ball around the vortex of existence, and that formula. Use of vortex force & Newton's gravitational the new formula, explain and calculate a lot of problems. The prediction of general relativity - inertial system drag (frame dragging) should be the vortex force.
2． By Kepler's idea of the sun's magnetic lines of a similar thing, we may wish to call it gravity line, The sun's rotation gravity-driven rotary, scroll to the transfer of the planets, scroll to the transfer of planets. The planets corner speed is less than the sun's rotation velocity resulting precession. Moon, too, was angular momentum away from Earth. If the satellite is the corner speed of the earth's rotation velocity, the satellite is not cutting gravity line from the vortex of . Geostationary satellite is the case. If the satellite is greater than the corner of the earth's rotation velocity speed, scroll of satellite impede movement, the angular momentum to reduce satellite orbit decay decline , thousands of man-made celestial bodies are so, the Mars satellite Phobos as well.
3． No rotation of the sun's or rotation corner velocity is less than the rotation corner speed of Mercury, Mercury can not be precession, moving instead to retire. So with the solution of Schwarzschild Mercury precession [Newton's theory of deviation], I can not agree. If the inertial system drag of general theory of relativity to explain the Mercury precession, I think But good. Einstein was the problem with Mercury moving into the capture of the stronghold of Newton, is now a directional errors.
4. Solve the Mercury precession [Newton's theory of deviation] There are many ways to the present, there is more than 10 domestic, but with the added vortex of gravitational theory to explain primary and secondary school students will be able to understand [qualitative analysis] and high school students can quantitative analysis.
5. Reflection: no force act, no angular momentum transfer, no energy conversion, the Mercury can precession [Newton's theory of deviation]？？
Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 27/05/2008 12:36:34
That all makes no sense at all.
First learn some proper Science, then come back with a valid objection to it.
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 28/05/2008 08:41:15
Use  Cavendish torsion balance measuring gravity tangential component (Vortex  force)
zhuyonghuan

Gravitational constant G = π ^ 2 * b * 2 * ds / M * L * T ^ 2
Where: M: quality of the big shot  put
T: torsion balance vibration cycle. T=220s
b: size of the ball from centr.
d: small ball long arm . d=5.0cm
L: Projection-point distance. L=2.70m
S:  laser  -point shift distance[ With the magnifying glass observation ]
1.To test the ball rotation on the ball at the role of the need to re-design of the experiment. As shown in Figure 6- 2, the ball will be placed on rotating platforms, the near-equatorial plane ball, the shaft vertical water level，For the anti-vibration, rotary tese desk and torsion balance on two test desk  around  without contact with the experiment, tese test desk legs and the use of ground vibration isolation pad, the test ball must be carried out  shield.
-   As vertical view 6- 2
-   Slowly but steadily turning the ball found a mobile laser point, (generally a cycle). Testing the ball moving along the direction of the ball rotation tangent direction, overlooking seen in Figure6- 2. Existing gravity at the center of mass, said by law to the component Fn said that the new found power to the component of the vertical direction along the tangent, said tangential component used Ft said，Below a few small experiments conducted on the Ft step in the exploration and research. 1500 g ball for the shot put, the center of mass pitch 7.5 cm, as are anti-clockwise, clockwise negative，This device, mobile-1 mm, the force of about 2.50 * 10 ^ -10 Newton.
-   Table 6-1
Large ball to move from,    s (mm)    , Speed (cycle / sec)
-Anti-clockwise -------- 0.5 --------------- 1.0
-Anti-clockwise -------- 0.6 --------------- 1.0
-Anti-clockwise -------- 0.4 --------------- 1.0
-Anti-clockwise -------- 0.5 --------------- 1.0
-Clockwise -------(-) 0.4 ------------- 1.0
-Clockwise -------(-) 0.5 ------------- 1.0
-Clockwise -------(-) 0.6 ------------- 1.0
-Anti-clockwise -------- 0.25 -------------- 0.5
-Anti-clockwise -------- 0.3 --------------- 0.5
-Anti-clockwise -------- 0.2 --------------- 0.5
-Clockwise -------(-) 0.3 ------------- 0.5
-Clockwise -------(-) 0.2 ------------- 0.5
-Clockwise -------(-) 0.25 ------------ 0.5
-   In table 6-1 make map, see Figure 6- 3
-   Figure 6- 3 sections:
(1) the ball in the direction of the ball along the direction of rotation tangent
-   (2) of the size and speed-related, similar proportional relationship, Ft α ω
-
-2. Ft on the quality of relations
-   Moment of the ball for 1 kg weight, 500 g weight, 50 g Hollow Copper Balls, the center of mass from 7.5 cm
-Large-type mobile ------ distance (mm) - Speed
-1 kg weight -------- 0.4 ------------ 1.0
-1 kg weight -------- 0.3 ------------ 1.0
-500 g weight ------- 0.2 ------------ 1.0
-500 g weight ------- 0.15 ----------- 1.0
-50 g Hollow Copper Balls ---- 0.00 ----------- 1.0
-50 g Hollow Copper Balls ---- 0.00 ----------- 1.0
-   Conclusion: (1) Ft similar proportional relationship with the quality, Ft α M
-                       (2) Hollow Copper Balls, although the diameter of the ball rotation with other similar, but their quality is too small, they have their rotation Ft minimal, but also equipment that sealing performance, and no air interference.
-3. in the direction of research: 1500 g ball for the shot put, from the center of mass to 7.5 cm, see Figure 6- 4 Figure 6 -4
-Offset angle - displacement (mm) --- angular velocity ω/2π
-   30 degrees ----------- 0.1 ------------ 1.0
-   60 degrees ----------- 0.25 ----------- 1.0
-   90 degrees ----------- 0.00 ----------- 1.0
-   0 degrees ------------ 0.5 ------------ 1.0
-   Summary: Ft two goals in the direction of heart connection with the vertical, rotating with the ball tangent direction of the same.
-4.Ft research center of mass and distance relationship.
-   1500 g ball with the shot put. Figure 6- 5
-
Spacing of heart - and displacement (mm )---, angular velocity ω/2π
-   7.5 cm ------- 0.50 ----------- 1.0
-   7.5 cm ------- 0.50 ----------- 1.0
-   10.0 cm ------- 0.25 ----------- 1.0
-   10.0 cm ------- 0.25 ----------- 1.0
-Conclusion: as shown in Figure 6- 5, When the ball when the M's rotation, the gravitational force between the two goals not only to the amount of Fn, but tangential component Ft, that is,
-   F = Fn + Ft ...... ④
-   ④- to the component Fn = GMm / r ^ 2, pointing to the direction of the other side of heart:
-   Ft for the tangential component, and Fn vertical direction, along the tangent direction of rotation of the ball, as shown in Figure 6- 5:
-   Ft = cosa * GMm ω k / r ^ 2 ...... ⑤
K = 0.4 for one factor,the unit:  sec/cycle  ; ω is the angular velocity rotating ball, the unit: cycle / sec; α to the orbital inclination.
Reference: With  Cavendish torsion balance experiment measuring gravity tangential component "and" physical communications 2002.9 "
mysterious vortex force- gravity partner Books Author: Zhuyonghuan Publisher: 21st Century Publishing House - China 2005-3
Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 29/05/2008 00:17:45
Is this a report of an actual experiment that was carried out?
Or is it just an advert for a book?
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 29/05/2008 02:17:02
With near 20years explore the more than 300 people each repeated verification; used Cavendish torsion balance measured vortex force of existence, and that formula New gravitational formula in the 2001 :
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 29/05/2008 02:23:20
new formular first solution about Pioneer10 slowdown in
2002-12.
Title: The most simple and reasonable solution about mercury precession
Post by: Bored chemist on 29/05/2008 19:27:35
I don't know what this thread is, but if it is trying to sell me a book, it is failing utterly.
I prefer books that make sense.
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 30/05/2008 01:56:50
Only Chinese version of the book, I have no intention to advertise in the United Kingdom.
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 02/06/2008 09:10:34

the sun, planets and the moon, the rotation cycle, quality, spin, and several satellite tables:
Name------radius r --- ----- rotation cycle T --- quality M --- vortex force Ft = KG ω Mm / r ^ 2 --- number of satellite
Earth ----- 1.0 -------- 1.0 -------- 1.0 -------------- 1.0---------- ----- 1
Sun ----- 109 -------- 25 --------- 3 * 10 ^ 5 ----------- 1.01-------- ------ 9
Moon ----- 0.272 ------ 30 --------- 0.012 ------------ 0.0054------------ 0
Mercury ----- 0.38 ------- 59 --------- 0.055 ------------ 0.0065------------ 0
Venus ----- 0.95 ------- 244 -------- 0.82 ------------- 0.0037------------ 0
Mars ----- 0.53 ------- 1.026 ------ 0.11 ------------- 0.38-------------- 2
Jupiter ----- 11.2 ------- 0.41 ------- 318 -------------- 6.18------------ -- 61
Saturn ----- 9.4 -------- 0.44 ------- 95 --------------- 2.44---------- ---- 31
Uranus --- 3.8 -------- 0.7 -------- 14.5 ------------- 1.43------------- -22
Neptune --- 3.9 -------- 0.76 ------- 17 --------------- 1.47------------ -- 12
Pluto --- 0.50 ------- 6.4 -------- 0.17 ------------- 0.106------------- 1

Contrast planets, we can easily find : Quality similar to the planets, large vortex force of the owner of the satellite and more, but less or no satellite. Vortex force of Jupiter's largest, with the largest satellite in planets; Saturn's spin of the second row, the number of satellites also ranked second; Although the quality of Mars than Venus, Mars due to the spin of less than 1%, so not only no natural satellites, and satellite access even more difficult than Mars.
Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 02/06/2008 14:14:20
Perhaps this would be more understandable in the original language  -if only I could understand that. Or perhaps you could get some help with translating your ideas into English.
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 03/06/2008 02:03:52

Dear Sir sophiecentaur : Hello!

I am a middle school physics teachers, Has been 30 years work in the laboratory,As I translate bad, to the readers bring difficulties, I am sorry! You can understand what I mean, I am very happy. If you can get the help, I would be very grateful.

Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 03/06/2008 09:47:37
Hi Z
I can't understand what you are getting at, I'm afraid. Can you refer me to any existing literature in English?
Title: The most simple and reasonable solution about mercury precession
Post by: zyh on 13/06/2008 10:01:16
vortex force Introduction of
In the beginning of  the last century, Astrophysicists face a problem, Mercury recently at the precession (Newton's theory deviation of: 43 angle seconds per century ), This is the quote the classics scholars can not explain, and it is not Newton's theory of classical mechanics adopted by a storm. Then only 37-year-old in 1916 Einstein published the《〈basis of general relativity〉》，Schwarzschild Metric German mathematician in the field equations of general relativity to the Mercury precession of the mystery，Mercury precession was therefore established the general theory of relativity early as the first major experiment. Later measured the Earth, Venus and other planets has also point precession of the general theory of relativity and the calculation of anastomosis with good results. Mercury precession and in the light deflection in the gravitational field, the gravitational redshift spectra of the three major criterion known as general relativity.
In the beginning of the new century, have an astrophysicist at the problems facing the front ，This is NASA  launched the "pioneers  10" "Galilean slightly," four spacecraft speed reduction. American scientists through 10 years of observation, found space for the role of a slowdown  The effect is tiny - only about one part in 10bn of that due to the Earth's gravity acting on you right now - but it is definitely there. So some scientists questioned Newton's Law of Universal Gravitation,
However, while some scientists believe that the best flight path is based on the parameters calculated, it is too early to doubt the basic law. We explore the long-term, in 2001, with  Cavendish  balance is measured not only by gravity to the component (that is, Newton's gravity), but also the existence of the tangential component, and that formula. To our planet, as an example, in addition to the original gravity (ie to the component), with the rotation of the earth, there are around in the vortex force of its (tangential component) the existence of ,The vortex force of (that is tangential component) and the Earth's rotation rate is proportional relationship. In the gravitational theory to elect representatives, it seems that non-Kepler, Newton and Einstein to my mind. It is worth noting that three representatives in the two agree that planets or stars in the rotation around a vortex. Kepler's idea of the same gravity as the car spoke, on the one hand to maintain the planets in their orbits can not run away (ie the components), on the other hand, with the sun's rotation around the sun forced planetary rotation (that is tangential component) . Einstein's general theory of relativity in there is a little-known forecast to be tested, the framework called gravitational drag [frame dragging]. When a planet or star rotation in space, it will drag space-time in its surrounding. This is very like the following example, when you filled with water in the bowl, one ball, and their rotation, the surface will be generated by the friction of water along the direction of rotation drag ball, the ball near the water in the rotation faster, the farther away from the ball, the friction of water drag effect will be weak. Newton's theory does not recognize the planet's rotation a scroll, so could not pass on Newton's theory of the "Mercury precession," this hurdle, a spacecraft can slow down this hurdle, Not only that, in many helpless astronomical phenomena, such as the angular momentum of the solar system, Venus reverse rotation  problems .
Practice is the sole criterion for testing theory, laboratory come to the conclusion also subject to the test of practice can rise to the theory.  use of vortex &  gravitational force formula, explain and calculate the following questions.

vortex force of 12 major criterion [quantitative calculation, high school students can master]

1. . the precession of the perihelion of Mercury's orbit (Newton's theory of deviation values.)
2. Venus precession 8.4 "± 4.8" per century. (Newton's theory of deviation values.)
3. Earth's precession 5.0 "± 1.2" per century. (Newton's theory of deviation values.)
4. "Pioneers 10" four spacecraft speed reduction. ( slowdown by the  the acceleration : one part in 10 billion of gravity at Earth's surface )
5.the moon Away from the Earth (3 cm per year).
6. Cycle of the Earth's rotation slows down. (Per hundred years 0.00164 s] ，
7. Coriolis force whereabouts eastward.
8. Around Mars Phobos campaign cycle to slow down the week 0.1 ms
9. Sun-synchronous orbit satellite orbital plane precession; altitude of 900 km polar orbit satellite orbital plane precession of the  daily 1 degree. The orbital plane of the vertical scroll relatively static, the situation in order to prove Scroll of the accuracy of the vortex force and an excellent opportunity.
10. Oblate of the Earth , 5 × 10-5m/s2. On the Global Positioning System GPS satellite orbit produces nearly 10,000 meters every day the impact of this phenomenon of vortex theory can be used to explain and calculate. Satellite orbit calculation of the largest perturbation of the - non-perturbation of the ball, not the flat rate from the Earth, but the role of the vortex.
11. Solar wind acceleration: time to reach the Earth, usually in the jet speed of 450 kilometers per second around.
12. With near 20years explore the more than 300 people each repeated verification;  used  Cavendish torsion balance measured vortex force of existence, and that formula
New gravitational formula in the 2001 :
F = Fn + Ft
To the weight of Fn = GMm / r ^ 2  -
Tangential component [vortex force] Ft = kGMm ω Cos α / r ^ 2
K = 0.4 for one factor,the unit:  sec/cycle  ; ω is the angular velocity rotating ball, the unit: cycle / sec; α to the orbital inclination.
Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 20/06/2008 08:43:04
vortex force:
1.Lab vortex force
a.used Cavendish torsion balance measured vortex force of existence, and that formula New gravitational formula in the 2001
2.earth vortex force
a.the moon Away from the Earth (3 cm per year).
b. Cycle of the Earth's rotation slows down. (Per hundred years 0.00164 s] ，
c. Coriolis force whereabouts eastward.
d. Sun-synchronous orbit satellite orbital plane precession; altitude of 900 km polar orbit satellite orbital plane precession of the daily 1 degree. The orbital plane of the vertical scroll relatively static, the situation in order to prove Scroll of the accuracy of the vortex force and an excellent opportunity.
e. Oblate of the Earth , 5 × 10-5m/s2. On the Global Positioning System GPS satellite orbit produces nearly 10,000 meters every day the impact of this phenomenon of vortex theory can be used to explain and calculate. Satellite orbit calculation of the largest perturbation of the - non-perturbation of the ball, not the flat rate from the Earth, but the role of the vortex.
3.solar vortex force
a. Mercury precession 43 "per century. (Newton's theory of deviation values.)
b. Venus precession 8.4 "± 4.8" per century. (Newton's theory of deviation values.)
c. Earth's precession 5.0 "± 1.2" per century. (Newton's theory of deviation values.)
d. "Pioneers 10" four spacecraft speed reduction.
e. Solar wind acceleration: time to reach the Earth, usually in the jet speed of 450 kilometers per second around.
4. Galaxy rotation curve flatness (dark matter, MOND theory).
5.Mars vortex force
a. Around Mars Phobos campaign cycle to slow down.

Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 02/09/2008 03:19:45
Pioneers 10 & 11 are found deceleration. Vorticity can predict the deceleration (one per ten billion of Earths gravity:g) by comparing Suns Vorticity near Earth to Suns Vorticity near Jupiter. Kants nebular hypothesis is the mostly widely accepted theory for solar system formation. However, Sun has less angular momentum than the hypothesis indicates. Vorticity can solve this angular momentum discrepancy. Sun transferred its angular momentum to its planets by Vorticity and then Suns rotation decelerated. Moon is moving away from Earth because Earth is also transferring its angular momentum to Moon by Vorticity. That is the reason of Earths rotation deceleration. The observed distance change (0.03 meter per year) can also be calculated by using Vorticity.
Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 02/09/2008 11:36:54
Is there a published paper about all this?
Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 04/09/2008 10:21:44
Dear Sir sophiecentaur : Hello!
published paper about all this in chinese:

1.用卡文迪许扭秤实验测引力切向分量《物理通报2002.9》

2.朱永焕。《神秘的涡旋力万有引力的伴侣》江西教育出版社电子书2003.3
3. 朱永焕。《神秘的涡旋力万有引力的伴侣》21世纪出版社2005.3
Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 23/09/2008 01:39:24

"A newly discovered universal force can help to develop unified theory

SIR-A newly discovered universal force called Vorticity can help to develop unified theory, discussed in your essay Unravelling string theory(Nature 438, 1085; 2005) The force was first discovered by Mr. Zhu based on a modified Cavendish experiment. I also used Keplers third law to independently deduct its formula later. A rotating mass has a vorticity force surrounding it. The force can drive object to move tangentially around a spinning mass. The formula is : KGMmωcosθ/R^2 (K=Vorticity constant=0.4, G=Gravity constant, ω=angular velocity(rev/sec), θ=angle between rotation plane of mass M and m, R=radius). Planetary movement equation is modified to be: GMm/R^2 + KGMmωcosθ/R^2=mRw^2

This new force is a force accompanying Gravity. Vorticity can explain many phenomenons such as Suns and Earths oblateness, planets precession(Earth, Venus, Mercury), Lense-Thirring effect, Pioneers 10 & 11 deceleration, Earths rotation deceleration(0.0016sec per hundred year), Moons orbit change, solar systems angular momentum transfer, and planets rings and satellites formation. A formula derived from Vorticity can well explain polar orbiting satellites precession: Ft=KGqMmωcosθ/R^2 (q=1-ωp/ωe, ωp=satellite orbital revolution velocity, ωe=Earth spinning velocity). Vorticity can also help to solve galaxy rotation problem by modifying virial mass (Mtotal=2(Rtotal*V^2)/(G+KGω), V=galaxy rotation velocity).

Pioneers 10 & 11 are found deceleration. Vorticity can predict the deceleration (one per ten billion of Earths gravity:g) by comparing Suns Vorticity near Earth to Suns Vorticity near Jupiter. Kants nebular hypothesis is the mostly widely accepted theory for solar system formation. However, Sun has less angular momentum than the hypothesis indicates. Vorticity can solve this angular momentum discrepancy. Sun transferred its angular momentum to its planets by Vorticity and then Suns rotation decelerated. Moon is moving away from Earth because Earth is also transferring its angular momentum to Moon by Vorticity. That is the reason of Earths rotation deceleration. The observed distance change (0.03 meter per year) can also be calculated by using Vorticity. (h=365*2GK^2*Mq/π^2*R^2, mgh=1/2*mū^2, ū=1/π∫vsinωtdωt=2at/π, a=KGMω/R^2, ū=daily average velocity of Moon)

The hypothesis that Uranus rings and satellites were formed in the beginning of solar system is widely accepted. Uranus rings and its satellites orbital revolution plane should have been in Suns ecliptic plane. An asteroid or comet hit Uranus and made its axial tilt of ninety-eight degree. Vorticity but not Gravity could force Uranus rings and satellites to move to the current rotational plane. Vorticity can also explain why rings are in the planets rotation planes and why only giant planets have rings. These above phenomenons can demonstrate that Vorticity really exists.

Because the slow rotation of Sun, Suns Vorticity is not significant comparing to its gravity. Thus, Keplers second law (conservation of angular momentum) is obeyed in planets of our solar system. However, Vorticity is still important in Pulsar or other fast-rotating stars and planets. The discovery of Vorticity can help to develop final unified theory and enhance our understanding of universe.

Wanchung Hu
Graduate Student,
National Taiwan University
No1, Ren-Ai Road,
Taipei, 100
Taiwan

Wanchung Hu

PhD candidate,

National Taiwan University, Johns Hopkins University"

Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 04/11/2008 01:37:22
Google:The Complement of Newton Gravitation Law
Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 13/11/2008 12:39:13
Give me the bottom line on this.
How big is this new force, compared with the force due to 'normal' Gravity?
It would need to be less than the spread of errors involved in all the established measurements or it would already have been revealed as a constant error, wouldn't it?
Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 14/11/2008 03:27:54
F = Fn + Ft
To the weight of Fn = GMm / r ^ 2  -
Tangential component [vortex force] Ft = kGMm ω Cos α / r ^ 2
K = 0.4 for one factor,the unit:  sec/cycle  ; ω is the angular velocity rotating ball, the unit: cycle / sec; α to the orbital inclination.

By the formula, we can see that:[earth]
Fn =216000 Ft

Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 14/11/2008 11:09:28
One point: angular velocity has the units of Radians per second (as opposed to frequency). Is your expression out by a factor of Pi?
Have you any measurements which reveal and confirm this factor of 1/2000,000? It's a tiny factor. If you obtained your value from the Moon's behaviour, is there any other data to support it?
As you know, there is an alternative mechanism which needs to be included. This is a real effect and needs to be factored into your sums.
Title: The most simple and reasonable solution about mercury precession
Post by: ZHUYH on 17/11/2008 06:48:07
Fn = GMm / r ^ 2
Tangential component [vortex force] Ft = kGMm ω Cos α / r ^ 2
By the formula, we can see that:[earth]

Ft = k ω Cos α Fn
Cos α=1,ω = 1/ 24×3600[cycle / sec] , K = 0.4 for one factor,the unit:  sec/cycle
Ft = [0.4/ 24×3600]Fn

=Fn/216,000
is  not:            1/2000,000
Title: The most simple and reasonable solution about mercury precession
Post by: lyner on 17/11/2008 10:33:26
Same comment as in the other thread - I slipped another zero into my post.
You still really need to put this force in context with the other forces in operation. Is it greater? Is it less? Is it a major factor or a tiny modification?