Naked Science Forum
Non Life Sciences => Chemistry => Topic started by: portugal on 22/08/2007 09:06:31
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When KBr reacts with conc. H2SO4 some bromine and SO2 are evident as well as the main product (HBr). The number of moles of KBr which reacts with one mole of conc. H2SO4?
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When KBr reacts with conc. H2SO4 some bromine and SO2 are evident as well as the main product (HBr). The number of moles of KBr which reacts with one mole of conc. H2SO4?
In which reaction?
2KBr + H2SO4 --> K2SO4 + 2HBr↑ or:
2KBr + 2H2SO4 --> SO2↑ + Br2↑ + K2SO4 + 2H2O?
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i will post the full question up ok unchanged:
1. When KBr reacts with conc. H2SO4 some bromine and SO2 are evident as well as the main product (HBr). The number of moles of KBr which reacts with one mole of conc. H2SO4 in this side reaction is:
a. 1.33 mol
b. 0.75 mol
c. 1.00 mol
d. 2.00 mol
e. 0.50 mol
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With the first reaction (only HBr) you have a molar ratio of 2/1
With the second (Br2 and SO2) you have a molar ratio of 1/1
You have both, so the only valid answer is with a value in between or answer A
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i will post the full question up ok unchanged:
1. When KBr reacts with conc. H2SO4 some bromine and SO2 are evident as well as the main product (HBr). The number of moles of KBr which reacts with one mole of conc. H2SO4 in this side reaction is:
a. 1.33 mol
b. 0.75 mol
c. 1.00 mol
d. 2.00 mol
e. 0.50 mol
With "this side reaction" it means: the one which forms SO2 and Br2. So you can see from the balanced reaction I wrote that it's 2 moles of KBr and 2 of H2SO4, that means 1 and 1. So the answer is 1 (c.)