Physics, Astronomy & Cosmology / Re: I visually ''see'' a beam of light in different time dimensions?« on: 06/07/2016 12:05:28 »
Yes exactly that, the rocket ship does not reach the sun at 12.16 and neither do we see arrive at 12.16, we see it arrive at 12.08 and that is the point you are missing that X is equal to Y.
Nobody says the rocket reaches the sun at 12:16.
The rocket reaches the Sun at 12:08. But we can't see that until 12:16.
Your x=y, and diagram, do not show the real situation. (Actually, it's not even clear what you're trying to show with them.)
The rocket takes 8 minutes to get to the Sun. Leaving at 12:00, it arrives at the Sun at 12:08, but nobody on Earth can see that yet. Light from that event starts to travel at 12:08. That light takes 8 minutes to travel to Earth. So it reaches Earth at 12:16. So utterly utterly simple.
The rocket reaches the Sun at 12:08, the Earth viewer sees it at 12:16. Simple.
For an Earth observer to actually see that 12:08 arrival, at 12:08, would require the light from that event to instantly travel to Earth from the Sun. That's your "unique" idea. i.e. the "0t" in your diagram in post #16 of this thread. That's not reality.