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Physics, Astronomy & Cosmology / Gas discharge tube hydrogen
« on: 16/03/2024 04:06:10 »
In the gas discharge tube experiment for H2, we have four emission lines in the visible spectrum. The explanation is that they are due to excited electrons that radiating according to the
formula:1/λ = R(1/nf? - 1/ni?) for nf= 2, ni = 3,4,5,6.
But QM requires that the electrons could only be excited by the exact frequency light (red, blue, violet, violet) in order to reradiate the four colors. But the source of the energy to the discharge tube is electrical, so how in the first place could the electrons get excited and reradiate. There are no visible light entering the discharge tube in the first place.
formula:1/λ = R(1/nf? - 1/ni?) for nf= 2, ni = 3,4,5,6.
But QM requires that the electrons could only be excited by the exact frequency light (red, blue, violet, violet) in order to reradiate the four colors. But the source of the energy to the discharge tube is electrical, so how in the first place could the electrons get excited and reradiate. There are no visible light entering the discharge tube in the first place.