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Physics, Astronomy & Cosmology / Re: Gas discharge tube hydrogen
« on: 16/03/2024 23:50:19 »Hi.Your reply is very helpful. I like to note that GDT works with AC/DC.The initial excitation is by collision with cations (in this case protons) streaming from the anode.Some if it is but there are also always going to be some free electrons to be found.
For one reason or another, there will be some atoms in the gas tube that are ionised so that we have a free electron and a positive ion (a "cation"). This might be a consequence of cosmic rays striking some atoms or something else. One way or another you have a tiny number of cations and free electrons in the gas, even though it might be a very small number.
Most gas discharge tubes work by causing an "avalanche effect". See https://en.wikipedia.org/wiki/Townsend_discharge for a description of the "Townsend Avalanche".
Basically if you have a small number of free electrons to start with and then accelerate them in an electric field, they have collisions with other atoms and quickly start to liberate more electrons and leave more positive charged ions. Under the right conditions the numbers of electrons increase geometrically (typically doubling on each collision). So fairly quickly you have a large number of free electrons and positive ions in the gas tube. There is a more detailed discussion in the Wikipedia page that was linked to.
Now let's go back to your ( @theThinker ) comments:But QM requires that the electrons could only be excited by the exact frequency lightThat's half right. If electrons were going to be moved from one orbit to another by absorbing a photon then those photons should have exactly the right amount of energy corresponding to the energy gap between the orbits. However, QM never said that absorbing a photon was the ONLY way to move electrons from one orbit to some other (or in this case to liberate them from the atom completely).
It is quite possible to liberate electrons through impact between the atom and some other particle. In our case, we have free electrons (and also some cations which can also be accelerated and get involved) these collide with the (un-ionised) atoms and liberate electrons from them.
Actually, if you just want to completely free the electron then you CAN also do this with photons and it's a lot less restrictive then trying to move them from one orbit precisely to another. See "the photo electric effect", https://en.wikipedia.org/wiki/Photoelectric_effect , provided the photons have energy greater than the ionisation energy then the electron can be freed and the surplus energy will usually just become kinetic energy that the electron leaves the atom with. However, that isn't what is done in gas discharge tubes - we just have electrons liberated as a consequence of collisions and impact energy.In the gas discharge tube experiment for H2, we have four emission lines in the visible spectrum.Once you have quite a few free electrons these will start to fall back into the ionised atoms. They don't usually go from being free electrons straight to being bound in the lowest energy ground state of the atom. Indeed they will usually start at some higher orbit energy and steadily fall further down to lower energy orbits. Exactly as you have stated, some of these transitions will be to the final level n=2 from higher energy orbits (this is the Balmer series of emission lines). These are the ones which produce visible light. More discussion and diagrams available here: https://www.chemguide.co.uk/atoms/properties/hspectrum.html
I hope that helps.
Best Wishes.
I have a related question on the ionization part.The first process in gas discharge is ionization. It is easy to explain classically as the electric field applied pulls the nuclues and the electrons apart in opposite direction thus separating them.
But if we want a QM viewpoint, it may be difficult. An electron could be free of the nucleus only if it absorbs a photon raising its energy beyond the transition limit. But where do such an initial photon come from?
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