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Because of the equivalence principle, it is also true that if two clocks that are separated by a fixed distance "d" ly are both accelerated with a constant equal acceleration of "A" ly/y/y,
Now, suppose that he and his helper then both start accelerating at a constant "A" ly/y/y toward the right.
[...]What does HF see on her display? Does HF see that she is now slightly younger than 20?[...]