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Next , I already stated that the recoil is 1 pound average , same as a 1GW laser .
You aren't getting how it functions , and it's results .
A baseball with 1GJ energy is heavy artillery !
The peak forces would be tricky. :-)
If you can't even envision this simple of a mechanical system , you are NOT qualified to criticize me !
you are NOT qualified to criticize me !
Formulas are just a descriptor , NOT a concept !
Last time I lifted the lid , you were claiming that an average output of 1GW didn't have a 1lb recoil
I think you barfed up your word-salad here !
Meanwhile , just for shirts and grins , why don't you answer for b.c. above ?
Dooood ! Macro-physics won't work here ! I spent over 5 years chasing that wild goose ! To mimic micro-physics you must assume that 99% of the photonic-rocket energy is translated into the kinetic energy of the ball . This is what H.E.X-rays do to electrons . The power of the impact that you calculated would happen with every ball , once a second . Acceleration would be almost instantaneous . Now , run it again properly , then congratulate me on my triumph !P.M.
take the energy contained in the "magic" ray (1GW) , change it into kinetic energy ,
What happens when those balls "artillery" strike the brick house ?P.M.
Acceleration would be almost instantaneous .
Macro-physics won't work here ! I
I spent over 5 years chasing that wild goose !
then congratulate me on my triumph !
...................Blind Guys !So solly to see you sprain your brains unnecessarily ! You don't need to make it that complicated , just dump in enough electrons to absorb the X-ray's energy , and you will get a 1GJ impact at the target . It's a simple logic exercise , light cannot impact effectively , electrons can . The practical details will be learned through experience , the basic design is what is important at this point . So you see , the creative mechanical designer SPANKS the rediculous number crunchers yet again !P.M.
I will simplify this down to baby food for you .
What happens to the track of the centre of the ball?BTW, I'm going to keep asking that question until you actually answer it.
since light does not boil electrons