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Secrets of the orbit of the moon.From the foregoing, we can conclude that:1) The Moon’s orbit is always extended along the Earth’s orbit and does not rotate counterclockwise, making one revolution in 8.8 years. https://en.m.wikipedia.org/wiki/Apsidal_precession2) It is believed that at perihelion, the moon is at 50 thousand km. closer to Earth than aphelion, why is this huge difference not visually observed? https://images.app.goo.gl/wmqRKPc9jzScCrB163) The earth is in the center of the ellipse of the moon and not to the side, this can be easily checked. By measuring the time of the movement of the moon, from the new moon to the full moon and from the full moon to the new moon.4) What force does not give the barycenter of the Earth and the Moon is in the center of the orbit of the Moon? http://regul238_f27w5b.radius-host.net/forum/zemlja-luna.gif
The moon does not move from the new moon to the full moon for about 15 days, and from the full moon to the new moon for about 14 days.
How about addressing the problem I raised (that 0.076 is larger than 0.072)?
Quote from: Yusup Hizirov on 28/06/2020 17:35:13The moon does not move, 15 days from the new moon to the full moon and 14 days from the full moon to the new moon. https://images.app.goo.gl/wmqRKPc9jzScCrB16Nobody said it did.So, rather than talking nonsense, why don't you explain why you keep posting stuff that is plainly wrong?
The moon does not move, 15 days from the new moon to the full moon and 14 days from the full moon to the new moon. https://images.app.goo.gl/wmqRKPc9jzScCrB16
Show the error.
Quote from: Yusup Hizirov on 23/06/2020 08:02:19Vl - Orbital velocity of the moon.Vz - Orbital velocity of the Earth.The orbital speed of the moon is one revolution in 720 hours.The orbital speed of the Earth is one revolution in 8760 hours.E ≈ 720/8760 ≈ 0,082Wrong.Because the correct answer, as measured in reality, is 0.0549Quote from: Yusup Hizirov on 23/06/2020 08:02:19The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E ≈ Vi / VzWhere Vi is the satellite orbital velocity.Vz - Orbital velocity of the Earth.The satellite orbital speed is one revolution in 24 hours.The orbital speed of the Earth is one revolution in 8760 hours.E ≈ 24/8760 ≈ 0.0027Wrong, because the eccentricity of geostationary satellites is variable. The range is from less than .0001 to 0.008.Your formula says it's sonstant, so your formula is wrong.Quote from: Yusup Hizirov on 23/06/2020 08:02:19The eccentricity of the Phobos orbit can be calculated by the following formula. E ≈ Vf / VmWhere Vf - Orbital velocity of Phobos.Vm - Orbital velocity of Mars.The orbital speed of Phobos is one revolution in 7.4 hours.The orbital speed of Mars is one revolution in 16488 hours.E ≈ 7.4 / 16488 ≈ 0.000448The real answer 0.0151Quote from: Yusup Hizirov on 23/06/2020 08:02:19The eccentricity of the Deimos orbit can be calculated by the following formula. E ≈ Vd / VmWhere Vd is the orbital velocity of Deimos.Vm - Orbital velocity of Mars.Deimos's orbital speed is one revolution in 30 hours.The orbital speed of Mars is one revolution in 16488 hours.30/16488 ≈ 0.0018The real value i 0.00024Quote from: Yusup Hizirov on 23/06/2020 08:02:19The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.THEY ARE NOT COMPILED FROM A FORMULA. THEY ARE REAL MEASURED VALUES.You get the wrong answer in every single case.Why are you sticking to this nonsense?
Vl - Orbital velocity of the moon.Vz - Orbital velocity of the Earth.The orbital speed of the moon is one revolution in 720 hours.The orbital speed of the Earth is one revolution in 8760 hours.E ≈ 720/8760 ≈ 0,082
The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E ≈ Vi / VzWhere Vi is the satellite orbital velocity.Vz - Orbital velocity of the Earth.The satellite orbital speed is one revolution in 24 hours.The orbital speed of the Earth is one revolution in 8760 hours.E ≈ 24/8760 ≈ 0.0027
The eccentricity of the Phobos orbit can be calculated by the following formula. E ≈ Vf / VmWhere Vf - Orbital velocity of Phobos.Vm - Orbital velocity of Mars.The orbital speed of Phobos is one revolution in 7.4 hours.The orbital speed of Mars is one revolution in 16488 hours.E ≈ 7.4 / 16488 ≈ 0.000448
The eccentricity of the Deimos orbit can be calculated by the following formula. E ≈ Vd / VmWhere Vd is the orbital velocity of Deimos.Vm - Orbital velocity of Mars.Deimos's orbital speed is one revolution in 30 hours.The orbital speed of Mars is one revolution in 16488 hours.30/16488 ≈ 0.0018
The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.
Quote from: Kryptid on 28/06/2020 17:38:35How about addressing the problem I raised (that 0.076 is larger than 0.072)?You're right
Quote from: Yusup Hizirov on 28/06/2020 18:11:29Quote from: Kryptid on 28/06/2020 17:38:35How about addressing the problem I raised (that 0.076 is larger than 0.072)?You're right(1km / s) / (30 km / s) = 0.33Eccentricity of the moon's orbit 0.026 - 0.077. https://en.m.wikipedia.org/wiki/Orbit_of_the_Moon
Now, why don't you explain why you keep posting stuff that is obviously wrong.
The hypothesis of the formation of a record super new moon.As we know, the length of the lunar ellipse depends on the orbital velocity of the Earth.Every month, in the phase of the new moon, the Earth’s orbital velocity rises, which increases the length of the lunar ellipse. At the same time, the height of the lunar ellipse decreases accordingly, due to which, in the new moon phase, the Moon becomes closer to the Earth. And as a result, a super new moon is formed.In winter at perihelion, the orbital velocity of the Earth rises.During the coincidence of the perihelion of the Earth and the new moon, the orbital velocity of the Earth reaches its maximum value, due to which a record super new moon and super full moon are formed.In the summer in aphelion, in the new moon phase, only the super new moon is formed.Calendar of record super moons. https://predicalendar.ru/wiki/moon/super-moon/December 3, 2017, SundayJanuary 2, 2018, TuesdayJanuary 21, 2019, MondayFebruary 19, 2019, Tuesday.https://en.m.wikipedia.org/wiki/SupermoonCriticism of the existing theory of record super moon.Super moon - occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the orbit of the moon. At a speed of one revolution in 8.8 years.It means:That every 8.8 years super moon happens.And given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, then the super moon lasts about a year.At the same time, if super moon occurs in perihelion, then in aphelion half a month later, a micro moon occurs.But such a natural phenomenon is not observed in nature.https://images.app.goo.gl/aRfBpPhE2eTMB3YaAhttps://en.m.wikipedia.org/wiki/Apsidal_precession2) What force rotates the orbit of the moon?3) Why the record-breaking super moon is not formed in the summer.4) Why, a record super new moon, is more than a super full moon.5) The major axis of the moon's ellipse is always elongated along the Earth’s orbit, and does not become perpendicular to the Earth’s orbit.https://images.app.goo.gl/aRfBpPhE2eTMB3YaA6) The orbits of the satellites of the planets do not rotate and are always elongated along the orbits of the planets. And the orbits of the planets are spinning.
Then why, a record super moon, occurs every year and not after 8.8 years.
Now, please answer the question.Quote from: Bored chemist on Yesterday at 18:52:18Now, why don't you explain why you keep posting stuff that is obviously wrong.
Super moon - occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the orbit of the moon. At a speed of one revolution in 8.8 years.
(1km / s) / (30 km / s) = 0.33
Quote from: Yusup Hizirov on 23/02/2020 11:49:26Super moon is an astronomical phenomenon that occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the moon's orbit. It means:1) That half a month after the super new moon, the micro full moon will come. https://images.app.goo.gl/aRfBpPhE2eTMB3YaA2) Given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, the super new moon and micro full moon, replacing each other, will last up to a year.https://en.m.wikipedia.org/wiki/Apsidal_precession
Super moon is an astronomical phenomenon that occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the moon's orbit.
Now, can you get back to the point?Quote from: Bored chemist on 28/06/2020 20:12:45Now, please answer the question.Quote from: Bored chemist on Yesterday at 18:52:18Now, why don't you explain why you keep posting stuff that is obviously wrong.
Given the fact that the moon’s orbit rotates extremely slowly
Apsidal_precession
The eccentricity of the orbit of the moon can be calculated by the following formula.E ≈ (Vz / Ss) / (Vl / Sz) = 0.000058 / 0.0018 = 0.032----------------Where Vz - Orbital velocity of the Earth - 0,00011 r / h.Ss - The distance from the Sun to the Earth is 150,000,000 km.--------------Where Vl - Orbital velocity of the Moon - 0.0013 r / h.Sz - Distance from Earth to Moon - 384,000 km.The eccentricity of the orbit of the moon varies, from 0.026 to 0.077).
Quote from: Bored chemist on 29/06/2020 22:39:46Now, can you get back to the point?Quote from: Bored chemist on 28/06/2020 20:12:45Now, please answer the question.Quote from: Bored chemist on Yesterday at 18:52:18Now, why don't you explain why you keep posting stuff that is obviously wrong.
Does it work for Phobos?Vz = 86,430 km/h Ss = 227,939,200 km Vl = 7,696.8 km/h Sz = 9,376 km/hE = (86,430/227,939,200)/(7,696.8/9,376)E = (3.7918 x 10-4)/(0.821)E = 4.6185 x 10-4The correct answer is actually 0.0151. So it's even more wrong for Phobos than it is for the Moon.
Check your calculations.
Quote from: Kryptid on 26/06/2020 05:55:48Does it work for Phobos?Vz = 86,430 km/h Ss = 227,939,200 km Vl = 7,696.8 km/h Sz = 9,376 km/hE = (86,430/227,939,200)/(7,696.8/9,376)E = (3.7918 x 10-4)/(0.821)E = 4.6185 x 10-4The correct answer is actually 0.0151. So it's even more wrong for Phobos than it is for the Moon.Check your calculations.