1. What are the protons number and electrons number carbon in CH3+? As I know carbon atom has 6 electrons and 6 protons in a neutral state but in this case 5 protons or 6 protons and how many electrons? 2. How do the carbon get positive charge on it?
In this reaction, How many electrons carbon anion has 7 or 8? I mean C- has 7 electrons or 8 electrons and H+ has one proton, how to H+ ion combine with H3C- ion to form CH4 because H+ ion needs 2 electrons? I am confused. Please show the mechanism.
As I know 'O' is neutral as O has the same number of protons(8 protons) and electrons(8 electrons). But O fulfills its octet getting 2 extra electrons. So the sign of O is O²⁻. So in this condition, why should I call oxygen stable? but why not should I call a neutral oxygen a stable element? Could you explain it, please?
As we know, Equivalent weight = molecular weight/number of H+ replaced So, in H2SO4, E = M/2 = 98/2 = 49g/equivalent of H+ 1. But in this reaction, NaOH + H2SO4 = NaHSO4 + H2O how to calculate the equivalent weight of H2SO4? 2. 2NaOH + H3PO4 = Na2HPO4 + H2O, How to calculate the equivalent weight of 'H3PO4'?
If we split 'NH₃', we get 'N³⁻' and 'H³⁺' and in 'NH₃', N is more electronegative than H. So 'H' should be in the left and the formula should be'H₃N' as in 'NaCl' where 'Cl' is more electronegative than 'Na' So could you explain why this structure in 'NH₃'?