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Physics, Astronomy & Cosmology / Can a dot product give the Schwarzschild metric?
« on: 21/05/2021 22:22:10 »
No Christoffel symbols, No tensors.
The dot product of two vectors of acceleration represents an “interaction” of acceleration. The vectors act upon the same point in space-time. Each vector is four dimensional.
The expansion of the dot product gives a “scalar field equation”.
If groupings and operators are suitably defined, the scalar field equation will return the Schwarzschild metric, no Christoffel symbols, no tensors.
Is this expansion a valid representation of a scalar field?
The math is attached.
The dot product of two vectors of acceleration represents an “interaction” of acceleration. The vectors act upon the same point in space-time. Each vector is four dimensional.
The expansion of the dot product gives a “scalar field equation”.
If groupings and operators are suitably defined, the scalar field equation will return the Schwarzschild metric, no Christoffel symbols, no tensors.
Is this expansion a valid representation of a scalar field?
The math is attached.