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Chemistry / Shrink ray or growth ray, how could they work?
« on: 22/11/2024 19:43:41 »
If I may, let me pollute this section with a thought experiment (I promise it turns into a chemistry topic!)
I recently watched the Movie "Honey I Shrunk the Kids" with my kids. An interesting discussion ensured about whether it actually would be possible to have a growth/shrink ray. I posited that it might not be impossible, but that it would almost certainly be unsurvivable.
In the movie the explanation was essentially that atoms are 99% empty space, so all you have to do is collapse it down a little bit or expand it a little bit. Tah dah!
But the chemist in me said, "Wait. Are there ways (even just very theoretically) to expand and contract orbitals, so that atoms and molecules are shrunk down? And if there were a way, what would that mean for the energy levels of the altered matter?
Could a person shrunk by even 20% still eat and breathe "normal" food and air? Probably not, I would think. If the atoms are actually different sizes then the chemistry would have to be different! It comes right from the QM equations (assuming those still apply).
I recently watched the Movie "Honey I Shrunk the Kids" with my kids. An interesting discussion ensured about whether it actually would be possible to have a growth/shrink ray. I posited that it might not be impossible, but that it would almost certainly be unsurvivable.
In the movie the explanation was essentially that atoms are 99% empty space, so all you have to do is collapse it down a little bit or expand it a little bit. Tah dah!
But the chemist in me said, "Wait. Are there ways (even just very theoretically) to expand and contract orbitals, so that atoms and molecules are shrunk down? And if there were a way, what would that mean for the energy levels of the altered matter?
Could a person shrunk by even 20% still eat and breathe "normal" food and air? Probably not, I would think. If the atoms are actually different sizes then the chemistry would have to be different! It comes right from the QM equations (assuming those still apply).