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After the separation there is no force acting on Voyager,
Einstein's happiest thought: "No force acting on 'free falling body'".
Quote from: Jaaanosik on 11/12/2021 18:22:16After the separation there is no force acting on Voyager,Yes there is; gravity.
Quote from: Jaaanosik on 11/12/2021 18:22:16Einstein's happiest thought: "No force acting on 'free falling body'".Voyager isn't a free-falling body. It's moving away from the Earth, not towards it. As such, it is moving up a gravitational potential. Some of its kinetic energy is constantly being changed into gravitational potential energy.
The energy didn't appear out of nowhere. The photon with the higher frequency simply removed a larger percentage of the total energy than the lower frequency photon did.
As far as I'm aware, the equivalence principle assumes a uniform gravitational field (which the Earth's is not).Alternatively, it may depend on the reference frame that the measuring is done in. I'm sure Halc will chime in if I've got that wrong.
In a sufficiently small laboratory, there is no experiment done entirely inside the laboratory which can tell whether the laboratory is in free fall in a gravitational field or in uniform motion in empty space.
For an observer inside the lab, that is true because the experimental equipment is in the same reference frame as the excited atom. So like I said, whether or not you measure a frequency difference depends on your reference frame relative to the atom.
In what reference frame are you asking the question?
It's a pity that Pete no longer is amongst us. I'm not totally sure what you are asking about here. If you're asking if different reference frames will see different energies then that is true. Inside that space station, assuming the observer being in a exact same frame of reference with what he observes, there shouldn't be any possibility of measuring different energies depending on ones location in a gravitational potential / field though. As far as I know? well, with a caveat, it's about displacements isn't it? As soon as that photon leaves it change your reference frame, you're no longer in a same frame of reference.=In a free fall that is, locally indistinguishable from a absence of gravity. A photon has no acceleration and should be able to be considered a point particle excited at different locations in a so called 'photon field' in where your measurement will define its existence.
How do we get more energy from the aphelion photon if no work is done between perihelion and aphelion?