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New Theories / Re: How Many Numbers Exist?
« on: Today at 03:26:19 »
Hi.
There's an infinite set of distinct transcendental numbers, T. These are real numbers that are not algebraic. Actually MOST of the real numbers are these, the algebraic numbers are countable so they are a tiny drop in the ocean compared to the transcendental numbers.
Anyway, you could just keep adding the transcendental numbers one at a time until you got bored.
You can cut down some of those intermediate sets of numbers if you put more of a restriction on your set of numbers. For example, instead of just asking for a set of numbers, insist that the new set of numbers is always a proper Field in its own right. These would be called Field Extensions. (Example: If you try to add π, then the field operations automatically generate π2, π3, ...., 1/π, ...., -π, .... (705 + 3/π), .... so to ensure the set really is closed under field operations you'd need all of these numbers added in one go).
None the less, I still think there's an infinite set of simple field extensions you could find. (I haven't spent too long thinking about it but I reckon you could try a simple field extension by adding π and show that √π is still missing, so extend again with √π and show the √(√π) is still missing..... etc..... the root of what you've just extended with should always be missing).
Best Wishes.
Is there a set of numbers which contains more than algebraic numbers but less than real numbers?If you just want a SET of numbers, yes, many of them.
There's an infinite set of distinct transcendental numbers, T. These are real numbers that are not algebraic. Actually MOST of the real numbers are these, the algebraic numbers are countable so they are a tiny drop in the ocean compared to the transcendental numbers.
Anyway, you could just keep adding the transcendental numbers one at a time until you got bored.
You can cut down some of those intermediate sets of numbers if you put more of a restriction on your set of numbers. For example, instead of just asking for a set of numbers, insist that the new set of numbers is always a proper Field in its own right. These would be called Field Extensions. (Example: If you try to add π, then the field operations automatically generate π2, π3, ...., 1/π, ...., -π, .... (705 + 3/π), .... so to ensure the set really is closed under field operations you'd need all of these numbers added in one go).
None the less, I still think there's an infinite set of simple field extensions you could find. (I haven't spent too long thinking about it but I reckon you could try a simple field extension by adding π and show that √π is still missing, so extend again with √π and show the √(√π) is still missing..... etc..... the root of what you've just extended with should always be missing).
Best Wishes.
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