21
New Theories / Re: How the Solar energy is created?
« on: 04/07/2023 01:24:35 »
Let's refer back to the link calculating tidal forces I posted earlier: https://www.astro.uvic.ca/~jwillis/teaching/astr201/maths.7.tidal_heating.pdf
According to the equation calculating the power of the tidal forces affecting Io, the total power is 6 x 1017 watts. The power is inversely proportional to the tidal cycle period, so if we reduce the period from the 1.769 days of Io to the 25.05 days of the Sun, that reduces the total power to 4.24 x 1017 watts. The power is also linearly proportional to the tidal force. Since the tidal force on the Sun from Alpha Centauri A is 50 million times lower than that of Io, then the power also reduces 50 million-fold to 8.47 x 108 watts.
The Sun's total power output is 3.828 x 1026 watts. If we assume (very, very generously) that tidal power is converted into heat with 100% efficiency, then the heights of the tides on the Sun would need to be 4.519 x 1017 times higher than they are on Io (according to the equation). Since Io's tidal heights are about 50 meters, that corresponds to tidal heights on the Sun of 2.26 x 1016 kilometers. That's over 16 billion times larger than the Sun's own diameter. So even if every star in the Milky Way (400 billion of them) could exert the same amount of tidal force on the Sun that Alpha Centauri A does (which, of course, is impossible because they are much too far away), that would still require tides nearly 112,000 kilometers high (about the size of the planet Saturn) on the Sun.
Since the Sun does not have such extreme tides (despite extremely unrealistic assumptions that would help your model), then we know that your model cannot possibly be correct.
According to the equation calculating the power of the tidal forces affecting Io, the total power is 6 x 1017 watts. The power is inversely proportional to the tidal cycle period, so if we reduce the period from the 1.769 days of Io to the 25.05 days of the Sun, that reduces the total power to 4.24 x 1017 watts. The power is also linearly proportional to the tidal force. Since the tidal force on the Sun from Alpha Centauri A is 50 million times lower than that of Io, then the power also reduces 50 million-fold to 8.47 x 108 watts.
The Sun's total power output is 3.828 x 1026 watts. If we assume (very, very generously) that tidal power is converted into heat with 100% efficiency, then the heights of the tides on the Sun would need to be 4.519 x 1017 times higher than they are on Io (according to the equation). Since Io's tidal heights are about 50 meters, that corresponds to tidal heights on the Sun of 2.26 x 1016 kilometers. That's over 16 billion times larger than the Sun's own diameter. So even if every star in the Milky Way (400 billion of them) could exert the same amount of tidal force on the Sun that Alpha Centauri A does (which, of course, is impossible because they are much too far away), that would still require tides nearly 112,000 kilometers high (about the size of the planet Saturn) on the Sun.
Since the Sun does not have such extreme tides (despite extremely unrealistic assumptions that would help your model), then we know that your model cannot possibly be correct.
The following users thanked this post: Bored chemist