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Except that F = ma, not ma2, F is a vector, not a scalar,c is a speed, not an acceleration.In other words, no, not at all.
I did not ask any of the above Alan , I asked E=mc² is exactly the same as F=ma² when (c) and (a) are accelerations of the same magnitude?
Quote from: Thebox liI did not ask any of the above Alan , I asked E=mc² is exactly the same as F=ma² when (c) and (a) are accelerations of the same magnitude?No. Those aren't the same. In fact F = ma^2 is dimensionally incorrect and not an equality.
I now want to know what is the acceleration of light if you are saying c is only a speed?
Take a simple situation where a = b + c. Say a = 10, b = 4 and c = 6. We can square both sides of the equation as in a^2 = (b + c)^2. To expand (b + c)^2 we first have (b + c)(b + c). This multiplied out gives b^2 + 2bc + c^2. Working this out we get a^2 = 10^2 which is 10 times 10 so that is 100. Now we have to find a value of 100 from b^2 + 2bc + c^2. b^2 is 4^2 which equals 16. c^2 is 6^2 which equals 36. So from those we get 16 + 36 which equals 52. Now we get to 2bc which is 2 times 4 times 6. So two times 4 is 8 and 6 times 8 = 48. Then adding 52 to 48 hey presto we get 100. Squaring values on both sides of an equation can be very useful when solving some types of equation.
As a good first step in advancing your understanding of probability a well known real life example is useful.https://en.wikipedia.org/wiki/Lottery_mathematics
F=m1*aF=M2*aF=ma²does this not describe a collision?If not sorry my misunderstanding.
E=mc² is exactly the same as F=ma² when (c) and (a) are accelerations of the same magnitude?
By the way "c" is speed whereas "a" is acceleration. Why did you think that the "c" in E = mc2 was acceleration?
No. c is a speed, not a velocity nor an acceleration.The speed of light does not vary in a vacuum. No variation = no acceleration.E = mc2 has nothing to do with photons colliding with the walls of a box. It is the energy released when masses annihilate, or the mass of particles produced when a photon interacts with a nucleus, or a whole lot of other stuff that Pete will go on about, bit nothing to do with momentum transfer.
Quote from: alancalverd on 11/09/2015 22:09:49No. c is a speed, not a velocity nor an acceleration.The speed of light does not vary in a vacuum. No variation = no acceleration.E = mc2 has nothing to do with photons colliding with the walls of a box. It is the energy released when masses annihilate, or the mass of particles produced when a photon interacts with a nucleus, or a whole lot of other stuff that Pete will go on about, bit nothing to do with momentum transfer.I should stress to people not to watch youtube videos of science , the thought experiment to Einstein's E=mc² shows a photon hitting an imaginary box. You mention annihilation of mass, do you mean like a Neutron star I think it was, that crushes protons?
I do not understand why E=mc² has a speed attached to it, or uses massless light when you say it is mass related.
Why would Energy be related to a speed and not a compression?
''The speed of light does not vary in a vacuum. No variation = no acceleration.''So are you saying that if I had a vacuum tunnel that was 299 792 458 meters long, light would take one second to travel the distance and this never alters?A clock constant that does not alter to a said time dilation like the materialistic values of the Caesium atom shows a frequency offset by gravity influence.
Energy = force x distance. In the case of adiabatic compression, the kinetic energy expended in compressing a hysteresis-free body resides as potential energy. But since force = mass x acceleration and acceleration = distance /time^2, so energy has the dimensions of mass x distance^2/time^2Speed has dimensions distance/time, so mc^2 has the same dimensons as energy.