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Physics, Astronomy & Cosmology / Re: Do matter and antimatter interact gravitationally?
« on: 01/05/2016 18:01:14 »Quote from: Matteroftime
Pmbphy, if i understand we assume that inertial mass is the same thing than gravitational mass, so antimatter should fall the same, right?Right. That holds for all particles. There's no reason to expect a positron (the antiparticle of the electron) to fall at a different rate than anything else. However, if, for some bizarre reason, certain particles fell at different rates than 9.8 m/s^2 then general relativity would have to be modified.
Quote from: Matteroftime
I am sorry i do not understand the second part, what is arbitrary?What is arbitrary is which particles are referred to as normal "particles" and which particles are referred to as "antiparticles." For instance the positron is said to be the antiparticle of the electron. It's also true that the electron is the antiparticle of the positron. So which particle is defined to be an "antiparticle" is completely arbitrary. The choices made as to which is which came about due to historical reasons only.
Here is the way that Dr. Matt Strassler explains it. From: https://profmattstrassler.com/articles-and-posts/particle-physics-basics/
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There are many confusions about antiparticles. You cannot look at an object and say whether it is a particle or an anti-particle; you can only say X is an anti-particle of Y, and so Y is an anti-particle of X. You can’t say Y is the particle and X is the anti-particle, or vice versa.I highly recommend reading the rest of what he wrote. It's quite educational and very well written. Anyway, that is precisely what I meant when I said In fact there is no distinction between a particle and its antiparticle, this convention is arbitrary. Most people don't know about this.
Another common misbelief about antimatter is particle/antiparticle annihilation. It appears that most layman, even some professional physicists, believe that when a particle is near its antiparticle the two will annihilate and yield only photons. That's wrong.
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