t = t0/(1-v^2/C^2)^1/2
t = time observed in the other reference frame.
t0 = time in observers own frame of reference (rest time)
v = the speed of the moving object
c = the speed of light in a vacuum
(And ^ = the exponent = 'raised to')
Let v = .95c
t0 = 10 years
We will solve for t which is the time that the earth bound brother measures.
t = 10/(1- (.95c)^2/c^2)^1/2
t = 10/(1- .95^2)^1/2
t = 10/ .312
t = 32 years (the time the earth bound brother measures)
==
Nope, not mine :)
Just shortened it.
And when it comes to reaching the speed of light for matter it seems to become a infinitely steep slope.
(https://www.thenakedscientists.com/forum/proxy.php?request=http%3A%2F%2Fwww.phy.olemiss.edu%2FHEP%2FQuarkNet%2Fgr_timedial.gif&hash=1144838f9e26590b92dfb348d7c01105)
But if you could?
Maybe you could see it as a variation of the Bekenstein bound? (http://www.thenakedscientists.com/forum/index.php?topic=25747.msg333528#msg333528) naively speaking, as they say? Those, ahem, Mega Boffins ::))
(phieew... All those little ^ What ever are they good for?
Only disturbs my tranquility they do:)