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Thanks Thebox for your messages ! Maybe I don't explain so well my device because so few people are interesting ?
And there is near no water, like that it is possible to put inside, not water, but a liquid more dense like mercury to increase the power density. For my device, I need only vacuum or some matter very lightweight, a gradient of pressure from gravity or from electrostatic or electromagnetism and a fluid. If the angle at start is lower, the deformation gives more energy. I calculated for a small angle it is good. The good news, it is I don't need a mass (in theory) and it is very good for the power because in a rotational device, I can turn at a very high angular velocity.
Good day dude, do you know if increased current flows through a system, it increases the electromotive force speed? Or is it amps that counts ?
And there is near no water, like that it is possible to put inside, not water, but a liquid more dense like mercury to increase the power density. For my device, I need only vacuum or some matter very lightweight, a gradient of pressure from gravity or from electrostatic or electromagnetism and a fluid. If the angle at start is lower, the deformation gives more energy. I calculated for a small angle it is good. The good news, it is I don't need a mass (in theory) and it is very good for the power because in a rotational device, I can turn at a very high angular velocity.If I use that shape for a practice motor, I can use 2 rotors, upper is the ground of the device I drew, lower is the wall that move in translation. Two rotors turn at an angular velocity. The angular velocity of the lower rotor is variable, more or less, like that the lower wall can moves to the right (I increase the angular velocity of the lower rotor) to give an energy and move to the left (I decrease the angular velocity of the lower rotor) to return to the start position. The devices are between the 2 rotors, all around the perimeter, for example with 10 basic devices: frt2.png (52.34 kB . 960x484 - viewed 3205 times)
Don't you think it is better to verify the calculations before to increase the solutions ? Keep the goal in mind: break the belief about the energy I appreciate help about maths.
I stay focus on my goal For the device of 1 m³ and gravity of 10N/s² and move out/in the white part (near no water inside the device):For a small angle of rotation, for example δ=0.1°, from 45° to 45.1° the volume that move out/in is √2δ*1*1, so the energy for move out/in is √2δ*1*1*5000 = 12.34 J (δ=1.74e-3 rd). The energy to rotate the white rectangles is 10000*√2/2*1/√2*δ = 8.72 J (10000 N is the buoyancy force, the force is situated at √2/2, the force of buoyancy is at 45° so I need to divide by √2).Someone ?