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and you can disprove Fermats last theorem

when a integer 1 =a non-integer 0.999... maths ends in contradiction

0.999 ... a non-finite number

1 number (2) +1 number (2) =1 number (4) .... therefore 1+1=1

if a theory is inconsistent it will contain every sentence of the language

So with each opponents view being valid so there is no need/point to argue anymore

0.(9) seems ...

Quote from: nilak on 21/01/2019 13:25:200.(9) seems ...To whom, and why?

0.999999...is the same as 1it's just 2 ways of writing the same number

You assume 9.999... is 10x0.999... But you need to demonstrate it first.

Quote from: nilak on 22/01/2019 10:56:16You assume 9.999... is 10x0.999... But you need to demonstrate it first.I don't think I need to show that you can multiply a number by 10 by moving the decimal point one place to the right.And I understand your point, but perhaps you might go back and answer my earlier questions; especially this oneWhat is the difference between the number of nines after the decimal point in both cases?

How many nines are there after the decimal point in 0.9999....How many nines are there after the decimal point in 9.9999....What is the difference between those two numbers?

0.9999.... however it is signified, means "not quite 1.0" so it can't even be numerically equivalent to 1, let alone an integer.

I don't know. ∞-∞ undetermined.

What is the difference between the number of nines?

You and like minded viewers are looking at the example with the preconceived notion that .999...equals 1.

If you read the wiki article on 'limits', you should understand.