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Quote from: hamdani yusuf on 09/09/2024 16:28:39Quote from: Bored chemist on 09/09/2024 11:29:55Quote from: hamdani yusuf on 08/09/2024 13:53:52The question is, which object is the hottest? The electrons in the LED with an energy of a few electron volts, corresponding to a temperature of tens of thousands of kelvin.Does it melt? How the F*** do you expect an electron to melt?
Quote from: Bored chemist on 09/09/2024 11:29:55Quote from: hamdani yusuf on 08/09/2024 13:53:52The question is, which object is the hottest? The electrons in the LED with an energy of a few electron volts, corresponding to a temperature of tens of thousands of kelvin.Does it melt?
Quote from: hamdani yusuf on 08/09/2024 13:53:52The question is, which object is the hottest? The electrons in the LED with an energy of a few electron volts, corresponding to a temperature of tens of thousands of kelvin.
The question is, which object is the hottest?
How could you think that it referred to electron instead of LED?
Quote from: hamdani yusuf on 10/09/2024 08:13:30How could you think that it referred to electron instead of LED?Because it's totally obvious to anyone that the LED doesn't melt.
Quote from: Bored chemist on 10/09/2024 12:18:59Quote from: hamdani yusuf on 10/09/2024 08:13:30How could you think that it referred to electron instead of LED?Because it's totally obvious to anyone that the LED doesn't melt.What's the temperature of the LED? Why it's different from the temperature of the electrons?
The electrons do not, in this instance, have a well defined temperature.
The electrons in the LED with an energy of a few electron volts, corresponding to a temperature of tens of thousands of kelvin.
Within the chip, the active electrons responsible for light emission obviously have mean energies of the order of visible photons, 2 - 4 eV. 1 eV ≈ 11,605 K
Quote from: Bored chemist on 10/09/2024 18:29:17The electrons do not, in this instance, have a well defined temperature.Then why did you write this statement? Quote from: Bored chemist on 09/09/2024 11:29:55The electrons in the LED with an energy of a few electron volts, corresponding to a temperature of tens of thousands of kelvin.
Quote from: alancalverd on 10/09/2024 14:10:06Within the chip, the active electrons responsible for light emission obviously have mean energies of the order of visible photons, 2 - 4 eV. 1 eV ≈ 11,605 KWhy don't they cause the LED to melt down?
Did you not notice that I said the energy corresponded to a temperature, not that the electrons were at that temperature?
Quote from: hamdani yusuf on 10/09/2024 22:22:56Quote from: alancalverd on 10/09/2024 14:10:06Within the chip, the active electrons responsible for light emission obviously have mean energies of the order of visible photons, 2 - 4 eV. 1 eV ≈ 11,605 KWhy don't they cause the LED to melt down? Because someone has cleverly arranged things so that it's more likely that they will lose that energy by emitting light than that they will transfer it to thermal energy,
Tryhttps://electronics.howstuffworks.com/led.htm
LEDs generate very little heat, relatively speaking. A much higher percentage of the electrical energy is going directly to generating light, which cuts down the electricity demands considerably.
Quote from: Bored chemist on 11/09/2024 10:54:27Did you not notice that I said the energy corresponded to a temperature, not that the electrons were at that temperature?How are they correlated? Is it proportionally? Or inversely proportional? Or another type of correlation?
Quote from: Bored chemist on 11/09/2024 10:57:59Quote from: hamdani yusuf on 10/09/2024 22:22:56Quote from: alancalverd on 10/09/2024 14:10:06Within the chip, the active electrons responsible for light emission obviously have mean energies of the order of visible photons, 2 - 4 eV. 1 eV ≈ 11,605 KWhy don't they cause the LED to melt down? Because someone has cleverly arranged things so that it's more likely that they will lose that energy by emitting light than that they will transfer it to thermal energy,How is it done?
But when the light produced by LED hit the paper, it burns.
But when the light produced by LED hit the paper, it burns.In the video, there is a segment where the light is reflected back to LED using a mirror. The LED breakdown as a result.
Quote from: hamdani yusuf on 12/09/2024 14:37:40But when the light produced by LED hit the paper, it burns.In the video, there is a segment where the light is reflected back to LED using a mirror. The LED breakdown as a result.What do you expect? Photons deliver energy to the absorber.