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Non Life Sciences => Chemistry => Topic started by: doubleU on 16/10/2009 22:44:26

Title: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: doubleU on 16/10/2009 22:44:26
if you put 5.00g of solid NaOH in 100ml of water at the temp of 25 C, what is the final temp of the system?you need the specific heat of NaOH? specific heat= ?
the solution will heat up. Do we plug in 25 C for both ?
is the equation: msΔt NaOH = msΔT water??

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Title: Re: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: RD on 16/10/2009 23:23:24
You need the "Heat of Solution" for NaOH to predict the final temperature ...

Quote
For a given solute, the heat of solution is the change in energy that occurs as one mole of the solute dissolves in water.
http://pulse.pharmacy.arizona.edu/resources/heatofsolution.pdf

["Specific heat" capacity  (http://en.wikipedia.org/wiki/Specific_heat_capacity)is not the same as "heat of solution"].
Title: Re: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: doubleU on 16/10/2009 23:48:44
i got the final heat to be 38.2
Title: Re: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: RD on 17/10/2009 06:31:33
Title: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: lightarrow on 17/10/2009 11:53:42
if you put 5.00g of solid NaOH in 100ml of water at the temp of 25 C, what is the final temp of the system?you need the specific heat of NaOH? specific heat= ?
the solution will heat up. Do we plug in 25 C for both ?
is the equation: msΔt NaOH = msΔT water??
From the .pdf file provided from RD:
http://pulse.pharmacy.arizona.edu/resources/heatofsolution.pdf

in the simplistic hypothesys that the specific heat of the solution is the same as that of water, and assuming that the initial temperature of the solid NaOH is 25°C as well, we have:

moles of solute = 5g/(40g/mol) = 0.125 mol NaOH

molar heat of solution: ΔHsolution/(moles of solute) = -44.2kJ/mol

heat of solution: ΔHsolution = -44.2kJ/mol • 0.125 mol = -5.525kJ

masssolution = 5g + 100g = 105g = 0.105kg

ΔTsolution = -ΔHsolution/(masssolution • specific heatsolution) ≈

≈ -ΔHsolution/(masssolution • specific heatwater) =

= 5.525kJ/(0.105kg • 4.184kJ/kg°C) = 12.58°C.

So the final temperature would be: 25°C + 12.58°C = 37.58°C.
Title: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: Nizzle on 28/10/2009 10:10:35
Good job doing doubleU's homework lightarrow [:P]
Title: What temperature change occurs when solid sodium hydroxide dissolves in water?
Post by: lightarrow on 28/10/2009 11:16:13
Good job doing doubleU's homework lightarrow [:P]
I answered just because I considered it as an interesting problem for all readers. Of course it's not my habit doing others' homeworks  [;)].