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Physiology & Medicine / Re: Is Menthol Safe?
« on: 16/01/2025 13:11:04 »I've just realised that Lockets throat lozenges make a cough and sore throat worseWhat's the evidence base for that assertion?
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I've just realised that Lockets throat lozenges make a cough and sore throat worseWhat's the evidence base for that assertion?
In this scenario, we get an increase in system entropy without any change in temperature nor internal energy.Lucky us!
I think it's necessary, since you didn't seem to realize how insignificant it was.As I said,
you don't know what the phrase "in principle" means.
IMO, the biggest factor in determining P vs NP problem is because the problem isn't well structured/defined.And is your opinion well informed?
Personally I would consider aspartame to be preferable to some of the other sweeteners, saccharin, acesulfame and sucralose as these are synthetic substancesCyanide and arsenic are natural.
aspartame is a peptide ester.Botulinum toxin is a peptide and I doubt that sticking a methyl group on it would affect its properties much.
Here's another thought experiment to check our understanding of temperature, and its relationship with entropy.
Two isolated containers each with 1 cubic meter volume. Their internal surface is perfectly elastic, thus doesn't absorb energy from molecules hitting it. A small pipe equipped with a closed valve is connecting those containers. Initially, the first container contains helium gas at STP, while the second container is at vacuum. The whole system is inside a space lab, isolated from outside world.
When the valve is opened, some gas molecules will move to the second container. Since the collision with the container walls are elastic, they maintain their kinetic energy. At equilibrium, the flow rate from the first container equals the reverse flow. The pressure of both containers become half of standard pressure. The temperature is still at standard temperature, according to ideal gas law, P.V=n.R.T
The gas, which initially occupied 1 cubic meter of volume, now occupy 2 cubic meter.
Why do you keep posting stuff that we clearly already know?
That's a lot of trouble to go to in order to show that you don't know what the phrase "in principle" means.The experiment in the video clearly shows this.But, in principle, your spinning magnet warms it up a bit.The effects are much less than Eddy current generated in metals, thus doesn't significantly change the temperature measurement.
Eddy Current Demo #electromagnetic induction #physics #physicsninja
But we know that glass melts at its melting temperature.We know that the melting point of something (when it has one- glass doesn't) is defined as the temperature where the liquid and solid phases are in equilibrium.
If you look carefully, you will se the only bits of the line where the temperature is constant are the bits where there are two phases in equilibrium.And, if it's not at equilibrium, it doesn't have a properly defined temperature.If that's the case, the curve below won't be possible because the temperature is measured while heat is being transferred to/from the system.
It will melt before reaching equilibrium.I know.
And it would melt
According to Kirchhoff's law of thermal radiation, a good absorber is also a good emitter for the same radiation frequency.There's a good chance that I told you about Kirchhoff's radiation law. I have cited it quite a bit in these pages.
Note that objects heated by radiation from incandescent lamps can have higher temperature than the glass surface of the lamps. This pose question about thermal contact. Is exchange of kinetic energy through radiation counted as thermal contact?
I spent several years working on "dynamic equilibrium" calorimeters for measuring ionising radiation dose rates. Long story but it was a cunning way of measuring millidegree temperature changes to better than 0.1% precision.So... not Joule's method.
The classic Callendar and Barnes continuous flow water calorimeter uses a similar principle.
Joule measured the rate of rise of temperature.If the magnet is spinning then viscous dag will heat the air near to it.We tend to consider the boundary layer a stationary in laminar viscous flow. And it would be a pity if Joule's determination of the mechanical equivalent of heat by stirring water was seriously wrong - his result was within 0.75% of the current value.
And then it won't be at equilibrium any more.
I'm unaware of many things that you just decided to make up. Mindreading isn't my forte.But you seem un\aware of the fact that a spinning magnet in air will heat the air, thus disturbing the equilibrium.You seem to be unaware that as an example, I put the spinning magnet inside a vacuum glass box. There will be no friction between the air and the spinning magnet. But the spinning magnet can still generate heat in nearby metals by inducing Eddy current.
Fairly well defined. But, in principle, your spinning magnet warms it up a bit.And, if it's not at equilibrium, it doesn't have a properly defined temperature.Does the surface of the sun have a properly defined temperature?
Does the corona of the sun have a properly defined temperature?
Being unaware of these effects can lead to erroneous measurement values.And the guy who can tell you about 5 different sorts of liquid in glass thermometers is almost certainly not "unaware of these effects".
Depends on the radiated peak power, and is only limited by the horizon.Pick one.
Like I said before on this board, using the singular form of you (which is thee and thou in English) fell out of use a couple hundred years ago.A lot of folk in the North of England don't agree with that assessment; and they sometimes use "ye" too.
No. They both show the temperature of the contents of the thermometer bulb. One is heated entirely by conduction from the air, one has an additional dynamo component.How can we measure the temperature of the air around the spinning magnet?
Long-range radar generally works in the kHz to MHz range where water vapor absorption is minimal.In clear air, what's the typical range of microwave radar?