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When I introduce the lane 2 and lane 3 cars, we swap parameters and set the car in lane 2 to make 10 marks per second as per the rate of second used for the 10 second duration between start and stop light in lane 2, this being 10% longer than a lane 1 second. The lane 2 car travelling in the lane 2 duration between start and stop light will now make 100 marks that are 1 metre apart.But the lane 2 car travelling in the duration of a lane 1 second will make 90 marks that are 1.1 metres apart...
Colin - I am disappointed that you have forgotten that the Lane 2 car is set to make marks at a 10% faster rate than a lane 1 second. I don't really see how the maths can be stated as not working without including this parameter.
Consider that 10s2=11s1 .....
Let me please check that you understand fully all the parameters.Lane 1 itself and the lane 1 car are using a standard second. The rate of second in lane 1 is equal for both the lane and the car.Lane 2 is using a second that is 10% longer than this standard second, but lane 2's car is using a second that is 10% shorter than this standard second.I already described that if we use the shorter second to measure the scenario, that the car will make 120 marks that are 1 metre apart...I already described that if we use the longer second to measure the scenario, that this will be synonymous to a lane 3 car in lane 1, (as in part 1 of thought experiment, where lane 3 car is making marks at 1.2 standard seconds), and the car will make 80 marks that are 1.2 metres apart......Now we are going to use the standard second to measure what both lane 2 itself and the lane 2 car are doing.The lane 2 car is running at 0.9 of a lane 1 standard second, and lane 2 itself is running at 1.1 of a lane 1 standard second...Lane 1 is observing the shorter rate of second moving through the longer rate of second.
Matey travelling alongside in his lane 1 car, in lane 1, observed the journey that lane 2 car(a) made in lane 2, timing the event via 10 seconds as per his lane 1 stop watch, and making a mark on lane 1 every time he saw lane 2 car(a) make a mark on lane 2...........Any better?
The maths of this scenario do not work with respect to what? What exactly are you imagining the goal of these maths to be?
do the maths work?
Actually what I'm describing with Matey is no different at-all from running a lane 2 car in lane 1.
You are thinking, I think (scratches head) on the basis that lane 1's time is going to affect lane 2 car(a)'s rate of marking.
I cannot make head nor tail of your interpretation of making 0.9 of a mark. A mark is a mark and cannot be broken down into fractions.