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They were called British Units in my physics books. Oh well.
To KryptidThe top equation is 7.67427E-45 according to your calculationsThe bottom equation is 2.44207873E-45 according to your calculationsThe ratio is 3.142515 now pi = 3.14159The pi shows in the equation but is missing in your calculationThe second number should be 7.67204E-45This is an error of 0.029 percent from the first number.
Mass M = Charge Q x Light Speed x constant
GG: Thanks for your effort. You did a good job matching the MKS and British systems. The equation is a standard type force equation so it should work in any system although I never thought of such things.
Bored Chemist says:By observation, no; it is not.The charge of a proton, an antimuon, a +ve pion, and a positron are all the same.The masses are all different.GG: Yes they have different masses. It is necessary to calculate how many positive, negative and bipolar dot-waves are in each particle. At the dot-wave level the charge and the mass are related by a constant which depends upon the system of units you are in. For the MKS system a dot-wave has a mass of 1.96867E-71 kilograms and a charge of 3.47119E-60 Coulombs
To KryptidNaked 2.21.20 5 pmThe left side of the equation is kilograms meters per second squared. This is mass time acceleration. F= mass x acceleration =kilograms meters/ second squared The right side of the equation for units isF = Uo Q Co Q Vb*/ RR where Co is the speed of light and Vb* is the velocity of expansion of the hydrogen atom Bohr radius and R is the distance between the two atomsSo we have Uo coulombs meters per second x coulombs meters per second / meters squared. Breaking the R R into two parts we getF = Uo [coulomb x meters/(second x meters)] x [coulomb meters/(second x meters)]We can then get rid of the metersF = Uo [(Coulomb/second) (Coulomb/second)F = Uo I I The force per unit length between two current carrying wires on the internet isF/L = Uo Ia Ib/ 2 pi R Since L and R are both meters, the force units areF = Uo Ia Ib = electrical permeability times the current in wire a time the current in wire b In any event the right side of the equation is a standard form of electrical force equation which is mass time the acceleration.
The whole purpose of the calculation was to produce a time of the universe since big bang equivalent to what the astronomers got in 1981-3.
A few years ago I had to add the cosine of 30 degrees to get the 13.78 billion years
The concern of my model is the underlying structure of the universe
As far as an electron with only one tenth the mass, that would require it to have one tenth the charge as well. Someday five hundred billion years from now, the electron will radiate enough dot waves to do that. Then it will explode and the universe will be gone.
GG: The amount of dot-waves within a photon is the equivalent rest mass of the photon divided by 1.96867E-71 kilograms which is the mass of a dot-wave.