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**Physics, Astronomy & Cosmology / Re: Does a particle's weight increase with speed? More on relativistic mass.**

« **on:**26/07/2016 01:17:40 »

If you accelerate proton to really really high velocity,

and hit it with other stationary proton,

there will be created proton-antiproton pair:

p+ + p+ -> p+ + p+ + p+ + p-

Input two particles are creating four particles on output.

Proton has rest-mass 938.272 MeV/c^2

Anti-proton (also) have rest-mass 938.272 MeV/c^2

So basically from kinetic energy of incoming particles there are created two new particles (proton and antiproton)..

Baryon Number conservation:

prior event: +1 +1

after event: +1 +1 +1 -1

+1+1=+1+1+1-1

BTW, kinetic energy in Special Relativity is not E.K.=1/2*m*v^2 but

E.K.=m0*c^2*gamma-m0*c^2

where gamma=1/sqrt(1-v^2/c^2)

Basically, subtract relativistic-mass from rest-mass, and multiply by c^2.

and hit it with other stationary proton,

there will be created proton-antiproton pair:

p+ + p+ -> p+ + p+ + p+ + p-

Input two particles are creating four particles on output.

Proton has rest-mass 938.272 MeV/c^2

Anti-proton (also) have rest-mass 938.272 MeV/c^2

So basically from kinetic energy of incoming particles there are created two new particles (proton and antiproton)..

Baryon Number conservation:

prior event: +1 +1

after event: +1 +1 +1 -1

+1+1=+1+1+1-1

BTW, kinetic energy in Special Relativity is not E.K.=1/2*m*v^2 but

E.K.=m0*c^2*gamma-m0*c^2

where gamma=1/sqrt(1-v^2/c^2)

Basically, subtract relativistic-mass from rest-mass, and multiply by c^2.