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**New Theories / Creating electricity from global warming**

« **on:**29/05/2008 10:32:34 »

Sophie Dave,

I wish I could devote more time on here, hopefully soon, in the meantime let me clarify where this thread is hopefully going.

Two questions need to be addressed.

1) How much power can be generated from the falling water 800,000 liters falling 250 meters through a 20 cm diameter pipe?

2) Can our Artificial Trees lift that much water?

We have a lot of confidence in our Artificial tree's ability to lift the water. Which as I alluded to earlier has to do with the apparatus used in the experiments to measure the energy required to evaporate 1 kg of water. Did any of you check it out? (remember water is not a good conductor of heat)

Question 1 has been very confusing, have you guys checked the link I gave for the formula I used? If not please check their example, I'll copy and paste it below.

If you could kindly point out the errors I made when working through the formula with our numbers I would be very grateful.

Below is the example reprinted from this website http://www.wvic.com/hydro-works.htm

Kind Regards

Blaine

I wish I could devote more time on here, hopefully soon, in the meantime let me clarify where this thread is hopefully going.

Two questions need to be addressed.

1) How much power can be generated from the falling water 800,000 liters falling 250 meters through a 20 cm diameter pipe?

2) Can our Artificial Trees lift that much water?

We have a lot of confidence in our Artificial tree's ability to lift the water. Which as I alluded to earlier has to do with the apparatus used in the experiments to measure the energy required to evaporate 1 kg of water. Did any of you check it out? (remember water is not a good conductor of heat)

Question 1 has been very confusing, have you guys checked the link I gave for the formula I used? If not please check their example, I'll copy and paste it below.

If you could kindly point out the errors I made when working through the formula with our numbers I would be very grateful.

Below is the example reprinted from this website http://www.wvic.com/hydro-works.htm

**Power = (10 feet) x (500 cubic feet per second) x (0.80) / 11.8 = 339 kilowatts**

To get an idea what 339 kilowatts means, let's see how much electric energy we can make in a year.

Since electric energy is normally measured in kilowatt-hours, we multiply the power from our dam by the number of hours in a year.

Electric Energy = (339 kilowatts) x (24 hours per day) x (365 days per year) = 2,969,000 kilowatt hours.

The average annual residential energy use in the U.S. is about 3,000 kilowatt-hours for each person. So we can figure out how many people our dam could serve by dividing the annual energy production by 3,000.

People Served = 2,969,000 kilowatts-hours / 3,000 kilowatt-hours per person) = 990 peopleTo get an idea what 339 kilowatts means, let's see how much electric energy we can make in a year.

Since electric energy is normally measured in kilowatt-hours, we multiply the power from our dam by the number of hours in a year.

Electric Energy = (339 kilowatts) x (24 hours per day) x (365 days per year) = 2,969,000 kilowatt hours.

The average annual residential energy use in the U.S. is about 3,000 kilowatt-hours for each person. So we can figure out how many people our dam could serve by dividing the annual energy production by 3,000.

People Served = 2,969,000 kilowatts-hours / 3,000 kilowatt-hours per person) = 990 people

Kind Regards

Blaine